Hi All,
I have an input below. If the term in the 1st column is equal, print the last row which 1st column is equal.In the below example, it's " 0001 k= 27 " and " 0004 k= 6 " (depicted in bold). Those terms in 1st column which are not repetitive are to be printed as well. Can any body help me... (9 Replies)
Lets say I have file.txt:
(Product:Price:QuantityAvailable) (: as delimiter)
Chocolate:5:5
Banana:33:3
I am doing a edit/update function.
I want to change the Quantity Available, so I tried using the SED command to replace 5, but my Price which is also 5 is changed instead.
(for the Banana... (13 Replies)
Hi, i have file f1.txt with data like:
CHECK
a
b
CHECK
c
d
CHECK
e
f
JOB_START
....
I want to match the last occurrence of 'CHECK' until the end of the file.
I can use awk:
awk '/^CHECK/ { buf = "" } { buf = buf "\n" $0 } END { print buf }' f1.txt | tail +2Is there a cleaner way of... (2 Replies)
hey guys, i have been trying to work this thing out with sed with no luck :confused:
i m looking for a way to replace only the first occurrence after a match
for example :
Cat
Realized what you gotta do
Dog
Realized what you gotta do
Sheep
Realized what you gotta do
Wolf
Realized... (6 Replies)
echo 'String#1 and String#2' | egrep -o -m 1 'String#.{1}'
String#1
String#2
I'm trying to just match the first occurrence of 'String#' + 1 character. I thought the "-m 1" switch would do that for me. Instead I get both occurrences. Can somebody provide some insight?
Thanks! (5 Replies)
Hi all,
I have an input file as below. I would like to count the occurrence of pattern matching 8th field for each line.
Input:
field_01 field_02 field_03 field_04 field_05 field_06 field_07 field_08
TA T TA T TA TA TA... (3 Replies)
Hi, i have file file.txt with data like:
START
03:11:30 a
03:11:40 b
END
START
03:13:30 eee
03:13:35 fff
END
jjjjjjjjjjjjjjjjjjjjj
START
03:14:30 eee
03:15:30 fff
END
ggggggggggg
iiiiiiiiiiiiiiiiiiiiiiiii
I want the below output
START (13 Replies)
Discussion started by: Jyotshna
13 Replies
LEARN ABOUT DEBIAN
z88dk-copt
copt(1) z88 Development Kit copt(1)NAME
copt - peephole optimizer
SYSNOPIS
copt file ...
DESCRIPTION
copt is a general-purpose peephole optimizer. It reads code from its standard input and writes an improved version to its standard output.
copy reads the named files for its optimizations, which are encoded as follows:
<pattern for input line 1>
<pattern for input line 2>
...
<pattern for input line n>
=
<pattern for output line 1>
<pattern for output line 2>
...
<pattern for output line m>
<blank line>
Pattern matching uses literal string comparison, with one exception: ``%%'' matches the ``%'' character, and ``%'' followed by a digit
matches everything up to the next occurrence of the next pattern character, though all occurrences of %n must denote the same string. For
example, the pattern ``%1=%1.'' matches exactly those strings that begin with a string X, followed by a ``='' (the first), followed by a
second occurrence of X, followed by a period. In this way, the input/output pattern
mov $%1,r%2
mov *r%2,r%2
=
mov %1,r%2
commands copt to replace runs like
mov $_a,r3
mov *r3,r3
with
mov _a,r3
Note that a tab or newline can terminate a %n variable.
copt compares each run of input patterns with the current input instruction and its predecessors. If no match is found, it advances to the
next input instruction and tries again. Otherwise, it replaces the input instructions with the corresponding output patterns, pattern vari-
ables instantiated,and resumes its search with the first instruction of the replacement. copt matches input patterns in reverse order to
cascade optimizations without backing up.
BUGS
Errors in optimization files are always possible.
SEE ALSO z88dk(1), z88dk-zcc(1), z88dk-z80asm(1), z88dk-appmake(1), z88dk-copt(1).
AUTHOR
z88dk was written by Dominic Morris <dom@z88dk.org>, and others.
01 December 2009 copt(1)