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Top Forums Shell Programming and Scripting assign var with set=a[5] not working Post 302480053 by novice_man on Tuesday 14th of December 2010 01:21:58 AM
Old 12-14-2010
assign var with set=a[5] not working

Hi Experts,

I'm having issue in assigning var with special character [], please see below for complete details.
Code:
 $ echo $SHELL
/bin/csh

$ cat bp
abd/asd/a[5]

$ awk -F "/" '{print $NF}' bp | awk '{print $1}'
a[5]

$  set a=`awk -F "/" '{print $NF}' bp | awk '{print $1}'`

$ echo $a 
echo: No match    <=============

$  set=a[5]
set=a[5]: No match. <============

Thanks for any help !!!

Last edited by Scott; 12-14-2010 at 03:13 AM.. Reason: Please use code tags
 

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IGAWK(1)							 Utility Commands							  IGAWK(1)

NAME
igawk - gawk with include files SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ... igawk [ all gawk options ] [ -- ] program-text file ... DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1). AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like @include getopt.awk in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path. OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports. EXAMPLES
cat << EOF > test.awk @include getopt.awk BEGIN { while (getopt(ARGC, ARGV, "am:q") != -1) ... } EOF igawk -f test.awk SEE ALSO
gawk(1) Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995. AUTHOR
Arnold Robbins (arnold@skeeve.com). Free Software Foundation Nov 3 1999 IGAWK(1)
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