No error but not executing Post: 302479423

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Top Forums Programming No error but not executing Post 302479423 by Corona688 on Friday 10th of December 2010 03:55:03 PM

12-10-2010

Registered User

Quote:

Originally Posted by gokult

But the program shows lot of errors now.

What errors? In what code? I can't see the changes you've made to your program from here.

Code:

#include<stdio.h>
#include<sys/types.h>
#include<sys/mman.h>
#include<stdlib.h>
#include<fcntl.h>
#include<sys/stat.h>
#include<unistd.h>
#include<signal.h>
#include<string.h>

main(int argc, char *argv[])
{
int fd,changes,i,random_spot,kids[2];
struct stat buf;
char *the_file,*starting_string="Finally got it! \n";
size_t starting=strlen(starting_string);
if (argc!=2)
{
fprintf(stderr, "Usage %s file_name \n",*argv);
exit(1);
}
if((fd=open(argv[1], O_CREAT | O_RDWR,0666))<0)
{
fprintf(stderr,"open error on file %s\n",*argv);
exit(3);
}
write(fd,starting_string,starting);
if(fstat(fd,&buf)<0)
{
fprintf(stderr,"fstat error on file %s\n",*argv);
exit(4);
}
if((the_file=mmap(0,(size_t)
buf.st_size,PROT_READ|PROT_WRITE,MAP_SHARED,fd,0))==MAP_FAILED)
{
fprintf(stderr,"mmap failure\n");
exit(5);
}
for(i=0;i<buf.st_size;++i)
{
if(the_file[i]>='0' && the_file[i]<='9')
the_file[i]='*';
// the program takes seventeen seconds to run with this in
// sleep(1);
}
printf("Parent done with changes\n");
 printf("The file now contains:\n");
write(STDOUT_FILENO, the_file, buf.st_size);
printf("\n");
exit(0);
}

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bswap

BSWAP(3)						     Linux Programmer's Manual							  BSWAP(3)

NAME

       bswap_16, bswap_32, bswap_64 - reverse order of bytes

SYNOPSIS

       #include <byteswap.h>

       bswap_16(x);
       bswap_32(x);
       bswap_64(x);

DESCRIPTION

       These macros return a value in which the order of the bytes in their 2-, 4-, or 8-byte arguments is reversed.

RETURN VALUE

       These macros return the value of their argument with the bytes reversed.

ERRORS

       These macros always succeed.

CONFORMING TO

       These macros are GNU extensions.

EXAMPLE

       The  program  below  swaps the bytes of the 8-byte integer supplied as its command-line argument.  The following shell session demonstrates
       the use of the program:

	   $ ./a.out 0x0123456789abcdef
	   0x123456789abcdef ==> 0xefcdab8967452301

   Program source

       #include <stdio.h>
       #include <stdint.h>
       #include <stdlib.h>
       #include <inttypes.h>
       #include <byteswap.h>

       int
       main(int argc, char *argv[])
       {
	   uint64_t x;

	   if (argc != 2) {
	       fprintf(stderr, "Usage: %s <num>
", argv[0]);
	       exit(EXIT_FAILURE);
	   }

	   x = strtoul(argv[1], NULL, 0);
	   printf("0x%" PRIx64 " ==> 0x%" PRIx64 "
", x, bswap_64(x));

	   exit(EXIT_SUCCESS);
       }

SEE ALSO

       byteorder(3), endian(3)

COLOPHON

       This page is part of release 4.15 of the Linux man-pages project.  A description of the project, information about reporting bugs, and  the
       latest version of this page, can be found at https://www.kernel.org/doc/man-pages/.

Linux								    2017-09-15								  BSWAP(3)

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