without using ls, just using echo so purely pattern matching
I can say echo */ <-- lists directories
but how would I match files? surely something like *!/ or * but neither work ?
it seems like there isn't much that I can put in but surely i should be able to put any ascii... (1 Reply)
Hi folks,
I need to stop printing a new line after echoing a string in KSH. i know bash provides
echo -n "string"
what is the ksh equivalent for this ? (3 Replies)
Hello,
I have lib file which contain a function that get text to print on screen by echo command.
Several scripts are inculde this lib and use this function.
Each one of them is written in different shell language (sh ksh & bash).
This causing some issues when using backslash charater as... (4 Replies)
Hi all,
Basically Im trying to put the current time in a script in BASH. Tried the watch command, but its not really what I want.
I will have lots of things in this script, current date and time being just a few).
Any ideas? (4 Replies)
Why does echo supress line breaks in bash?
I'm working on a script that starts like this:
words=`sort list.txt | uniq`
echo $words | wc -l
I need to number the lines and then do other stuff. I'd use jot, but it's not installed, so I hope I can get seq to do what I want. But first I need to... (2 Replies)
Newbie to bash here. I think this is fairly simple, but I have searched and cannot figure it out. In the code below, I am searching an array for an IP address, and then printing the IP address if found. However, I would like to print the actual variable found such as 2.2.2.2=2, but cannot figure... (1 Reply)
Hi,
I have a problem with passing a echo output into a variable in bash
file='1990.tar'
NAME='echo $file | cut -d '.' -f1';
echo $NAME
the result is
echo $file | cut -d . -f1
however with this one,#!/bin/bash
file='1990.tar'
echo $file | cut -d '.' -f1
the result is what I... (2 Replies)
Hi, I am trying to make a script to manage log. I want to write the name of the .gz I moved and the date :
for i in `ls $replog/*.gz`
do
echo " $i "
`echo $i date +%d:%m:%Y`
`echo $datee `>> $replog/mrnet.log
mv $i /var/log/vieux-logs
done
I need to echo... (10 Replies)
I'm trying to echo the release version of some of our Linux servers. Typically I do these types of things by "catting" a text file with the host names, "ssh-ing" to the host and running my string.
This is what I've written
for i in `cat versions.txt` ; do echo $i ; ssh $i cat /etc/issue |... (5 Replies)
I am writing a bash script that automatically generates a macro program.
I want to have an echo on multiple lines and getting an error
/home/chaos/instru-correct.sh: line 309: command line is: command not found
I am using
echo "# The general synopsis of the $mfl" \
... (2 Replies)
Discussion started by: kristinu
2 Replies
LEARN ABOUT CENTOS
shell-quote
SHELL-QUOTE(1) User Contributed Perl Documentation SHELL-QUOTE(1)NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS --debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.16.3 2010-06-11 SHELL-QUOTE(1)