Hi ,
I have three funcions f1, f2 and f3 .
f1 calls f2 and f2 calls f3 .
I have a global variable "period" which i want to pass to f3 .
Can i pass the variable directly in the definition of f3 ?
Pls help .
sars (4 Replies)
Hi.
Problem: I have to parse the payload of a packet. The payload could be in Big Endian Format (network byte order) or little. That depends on a flag present in the header of the packet.
Solution: A horrible solution could be to check for that flag everytime I have to read a field in the... (11 Replies)
This is my function which is creating three variables based on counter & writing these variable to database by calling another function writeRecord
but only one record is getting wrote in DB.... Please advise ASAP...:confused:
function InsertFtg
{
FTGSTR=""
echo "Saurabh is GREAT $#"
let... (2 Replies)
In gdb, I can call one function with command "call", but how can I step in the function? I don't want to restart the program, but the function had been executed, gdb will execute next statement, and I don't know how to recall the function. (4 Replies)
I have a script which does gunzip, zip and untar.
Input to the script is file name and file directory (where file is located)
I am reading the input parameters as follows:
FILENAME=$1
FILEDIR=$2
I have created 3 functions that are as follows:
1) gunzip file
2) unzip file... (2 Replies)
Hello All,
I would like to ask help from you on how to pass variable value from a function that has been called inside the function. I have created below and
put the variables in " ". Is there another way I can do this? Thank you in advance.
readtasklist() {
while read -r mod ver... (1 Reply)
Dear All.
I have a script, which process files one by one. In the script I have two functions.
one sftp files to different server
the other from existing file create file with different name.
My question is:
Will sftp function recognize files names , which are created in another... (1 Reply)
Hi,
I am having script which contains many functions. Need to print each function name at the starting of the function. Like below,
functionname()
{
echo "functionname"
commands....
}
I've tried like below,
func=`grep "()" scriptname | cut -d "(" -f1`
for i in $func
do
nawk -v... (4 Replies)
Hi All,
Good Day, seeking for your assistance on how to not perform my 2nd, 3rd,4th etc.. function if my 1st function is in else condition.
#Body
function1()
{
if
then
echo "exist"
else
echo "not exist"
}
#if not exist in function1 my all other function will not proceed.... (4 Replies)
Discussion started by: meister29
4 Replies
LEARN ABOUT DEBIAN
nautilus-scripts-manager
NAUTILUS-SCRIPTS-MANAGER(1) General Commands Manual NAUTILUS-SCRIPTS-MANAGER(1)NAME
nautilus-scripts-manager - easy tool for nautilus scripts management
SYNOPSIS
nautilus-scripts-manager [options]
DESCRIPTION
This manual page documents briefly the nautilus-scripts-manager command.
nautilus-scripts-manager is a program that allows any user to easily manage installed Nautilus scripts.
GENERAL OPTIONS -h, --help
Show summary of options.
-v, --version
Show version of program.
COMMANDS
One (and only one) of the following commands can be passed:
-e, --enable=ENABLE
Enable script ENABLE.
-d, --disable=DISABLE
Disable script DISABLE.
-l, --list-enabled
List enabled scripts.
-a, --list-available
List available scripts.
If no command is provided, the graphical interface is started.
OPTIONS -e, --position=POSITION
In conjunction with -e or -d: establish the position of the script (can be just a name, or a path with slashes - quote it if it con-
tains spaces).
SEE ALSO nautilus(1),
AUTHOR
nautilus-scripts-manager and this manual page were written by Pietro Battiston <me@pietrobattiston.it>.
This manual page was written for the Debian project (but may be used by others).
July 14, 2009 NAUTILUS-SCRIPTS-MANAGER(1)