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Full Discussion: php date script problem
Top Forums Shell Programming and Scripting php date script problem Post 302471899 by SkySmart on Monday 15th of November 2010 02:22:52 PM
Old 11-15-2010
php date script problem

i want to store the output of date into a variable and be able to echo out that variable in a sentence. but the below isn't working.

Code:
<?php

#$date_time  = date('Y-m-d H:i:s');
putenv("TZ=US/Eastern");
date_time = "date('h:i:s')."\n"";

echo ("<li>Today's date is:  ($date_time)</li>\n");

?>

i want the output to be something like:

Code:
Today's date is ($date_time).


Last edited by SkySmart; 11-15-2010 at 03:29 PM..
 

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DATETIME.MODIFY(3)							 1							DATETIME.MODIFY(3)

DateTime::modify - Alters the timestamp

       Object oriented style

SYNOPSIS
public DateTime DateTime::modify (string $modify) DESCRIPTION
Procedural style DateTime date_modify (DateTime $object, string $modify) Alter the timestamp of a DateTime object by incrementing or decrementing in a format accepted by strtotime(3). PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3). The function modifies this object. o $modify -A date/time string. Valid formats are explained in Date and Time Formats. RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure. CHANGELOG
+--------+---------------------------------------------------+ |Version | | | | | | | Description | | | | +--------+---------------------------------------------------+ | 5.3.6 | | | | | | | Absolute date/time statements now take effect. | | | Previously, only relative parts were used. | | | | | 5.3.0 | | | | | | | Changed the return value on success from NULL to | | | DateTime. | | | | +--------+---------------------------------------------------+ EXAMPLES
Example #1 DateTime.modify(3) example Object oriented style <?php $date = new DateTime('2006-12-12'); $date->modify('+1 day'); echo $date->format('Y-m-d'); ?> Procedural style <?php $date = date_create('2006-12-12'); date_modify($date, '+1 day'); echo date_format($date, 'Y-m-d'); ?> The above examples will output: 2006-12-13 Example #2 Beware when adding or subtracting months <?php $date = new DateTime('2000-12-31'); $date->modify('+1 month'); echo $date->format('Y-m-d') . " "; $date->modify('+1 month'); echo $date->format('Y-m-d') . " "; ?> The above example will output: 2001-01-31 2001-03-03 SEE ALSO
strtotime(3), DateTime.add(3), DateTime.sub(3), DateTime.setDate(3), DateTime.setISODate(3), DateTime.setTime(3), DateTime.setTimes- tamp(3). PHP Documentation Group DATETIME.MODIFY(3)
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