need to create lines from ones that begin with the field separator
Hello,
I need to modify an awk script to recognize the last field $NF when the line is split over more than 1 line.
In my input file the field separator is the exclamation mark ! so FS="!"
So here is my input file infile.txt, it has 2 records, the field separator is in bold:
INPUT
Code:
4888689!?!Change of PROD
!TX!?!DETAILS
!US!?!?!file_937_20101024_065520.txt
48887370!Change of PROD!?!?!cmt_det3_937_20101024_065520.txt
Before I do anything in the AWK script I need to be able recognize the last field for each line type.
For record type #1 the $NF (last field) is on a different line (I need to be able to get the last field for these) (AWK recognizes record one as being 3 different lines) ($NF would be file_937_20101024_065520.txt)
For record type #2 the $NF (last field) is on the same line (this is the way AWK would read most of them) ($NF would be cmt_det3_937_20101024_065520.txt)
So the rule would be:
If the field separator is the 1st character on the line then look at the previous line until the line does not start with the field separator and so then
$1 would be on the first line and the $NF will be at the end of the last line.
Then print the lines to an output file
OUTPUT
Code:
4888689!?!Change of PROD!TX!?!DETAILS!US!?!?!file_937_20101024_065520.txt
48887370!Change of PROD!?!?!cmt_det3_937_20101024_065520.txt
Hi
I need to check if field separator I am using in awk statement is " : ", for example:
TIME=12:59
HOUR=`echo "$TIME" | awk '{FS=":"; print $1}'`
MINUTES=`echo "$TIME" | awk '{FS=":"; print $2}'`
Is there a way to check within the above awk statement ?
Thanks for help -A (2 Replies)
Hi, all
I need to get fields in a line that are separated by commas, some of the fields are enclosed with double quotes, and they are supposed to be treated as a single field even if there are commas inside the quotes.
sample input:
for this line, 5 fields are supposed to be extracted, they... (8 Replies)
Hi,
I have a flat file with fields separated by a X'1F'
i have to fetch 4th field from second line.
please help me how to achieve it.
I tried with below command and its not working.
cut -f4 -d`echo -e '\x1f'` filename.txt
I am using SunOS.
Thanks in advance. (2 Replies)
I am trying to echo all fields except for the last field.
I want to include the field seperator, but it is removed.
echo "a;s;v;g" | awk -F ";" '{$(NF--)=""; print}'
a s v
I want an output like this:
a;s;v; (3 Replies)
Hi all,
I have an array in BASH and I need to change the IFS in order to split up it correctly.
Here an example:
array_test=(hello world+sunny)
for elem in ${array_test}; do
echo $elem
done
echo -e "\n changed IFS \n"
OLD_IFS=$IFS
IFS=+
for elem in ${array_test}; do
echo... (3 Replies)
Hi !
input:
111|222|333|aaa|bbb|ccc
999|888|777|nnn|kkk
444|666|555|eee|ttt|ooo|ppp
With awk, I am trying to change the FS "|" to "; " only from the 4th field until the end (the number of fields vary between records).
In order to get:
111|222|333|aaa; bbb; ccc
999|888|777|nnn; kkk... (1 Reply)
I need to set awk field separator to ";", but I need to avoid ";EXT".
so that
echo a;b;c;EXTd;e;f | awk -F";" '{print $3}'
would give "c;EXTd" (2 Replies)
Hi Experts ,
file :
- How to construct the awk filed separator so that $1, $2 $3 , can be assigned to the each "" range.
I am trying : awk -F"]" '{print $1}'
but it is printing the entire file. Not first field.
The desired output needed for first field... (9 Replies)
Hello All,
I have a file, but I want to separate the file at a particular record with comma"," in the line
Input file
APPLE6SSAMSUNGS5PRICEPERPIECEDOLLAR600EACH010020340URX581949695US
to
Output file
APPLE6S,SAMSUNGS5,PRICEPERPIECE,DOLLAR600EACH,010020340URX581949695,US
This is for... (11 Replies)
Hi All,
I have the input as below:
cat input
032016002 2.891 97.109 16.605 27.172 24.017 32.207 0.233 0.021 39.810 0.077 0.026 19.644 13.882 0.131 11.646 0.102 11.449 76.265 23.735 16.991 83.009 8.840 91.160 0.020 99.980 52.102 47.898 44.004 55.996 39.963 18.625 0.121 1.126 40.189... (15 Replies)
Discussion started by: am24
15 Replies
LEARN ABOUT V7
join
JOIN(1) General Commands Manual JOIN(1)NAME
join - relational database operator
SYNOPSIS
join [ options ] file1 file2
DESCRIPTION
Join forms, on the standard output, a join of the two relations specified by the lines of file1 and file2. If file1 is `-', the standard
input is used.
File1 and file2 must be sorted in increasing ASCII collating sequence on the fields on which they are to be joined, normally the first in
each line.
There is one line in the output for each pair of lines in file1 and file2 that have identical join fields. The output line normally con-
sists of the common field, then the rest of the line from file1, then the rest of the line from file2.
Fields are normally separated by blank, tab or newline. In this case, multiple separators count as one, and leading separators are dis-
carded.
These options are recognized:
-an In addition to the normal output, produce a line for each unpairable line in file n, where n is 1 or 2.
-e s Replace empty output fields by string s.
-jn m Join on the mth field of file n. If n is missing, use the mth field in each file.
-o list
Each output line comprises the fields specifed in list, each element of which has the form n.m, where n is a file number and m is a
field number.
-tc Use character c as a separator (tab character). Every appearance of c in a line is significant.
SEE ALSO sort(1), comm(1), awk(1)BUGS
With default field separation, the collating sequence is that of sort -b; with -t, the sequence is that of a plain sort.
The conventions of join, sort, comm, uniq, look and awk(1) are wildly incongruous.
JOIN(1)
11-03-2010
