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Top Forums UNIX for Dummies Questions & Answers find single quote in a string and replace it Post 302468548 by yogichavan on Wednesday 3rd of November 2010 06:19:15 AM
Old 11-03-2010
find single quote in a string and replace it

Hi,

I have variable inside shell script - from_item.
from_item = 40.1'1/16

i have to first find out whether FROM_ITEM contains single quote(').
If yes, then that need to be replace with two quotes ('').

How to do it inside shell script? Please note that inside shell script........
 

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ESCAPESHELLARG(3)							 1							 ESCAPESHELLARG(3)

escapeshellarg - Escape a string to be used as a shell argument

SYNOPSIS
string escapeshellarg (string $arg) DESCRIPTION
escapeshellarg(3) adds single quotes around a string and quotes/escapes any existing single quotes allowing you to pass a string directly to a shell function and having it be treated as a single safe argument. This function should be used to escape individual arguments to shell functions coming from user input. The shell functions include exec(3), system(3) and the backtick operator. On Windows, escapeshellarg(3) instead removes percent signs, replaces double quotes with spaces and adds double quotes around the string. PARAMETERS
o $arg - The argument that will be escaped. RETURN VALUES
The escaped string. EXAMPLES
Example #1 escapeshellarg(3) example <?php system('ls '.escapeshellarg($dir)); ?> SEE ALSO
escapeshellcmd(3), exec(3), popen(3), system(3), backtick operator. PHP Documentation Group ESCAPESHELLARG(3)
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