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Full Discussion: How to replace ^J in unix file
Top Forums Shell Programming and Scripting How to replace ^J in unix file Post 302468282 by G.K.K on Tuesday 2nd of November 2010 08:51:45 AM
Old 11-02-2010
I have done the file ftp and place it in AIX box. Now i am surprised with the source file... it is not showing any special character in the file when i opened through vi. but when i have given the command tail -1 input.txt.. it is not giving the last line , it is giving all the two lines from the source file.

file inut.txt:
-----------
20101021
1023

Below is the output after giving the command tail -1 input.txt:
20101021
1023

it is displaying all the lines from the source file Smilie. I am shocked tat why it is happening even though there is no special character visible in the file.
How to fix this. and identify the special character.
Please suggest how to fix it

Thanks In Advance
kk


Quote:
Originally Posted by ikki
When dealing with characters, that are not easy to type in an editor, I usually find the "offending" character with od. od can be found on most *nixes, and supports multiple ways to display it's input.

Here are a few examples. First I created some arbitary data:
Code:
perl -e 'print chr($_) for (1..10);' > some_data

And the outputs of od for that file:

Hexadecimal 2-byte output:
Code:
$ od -h < some_data
0000000 0201 0403 0605 0807 0a09
0000012

Hexadecimal 2-byte output with the characters next to it:
Code:
$ od -hc < some_data
0000000 0201 0403 0605 0807 0a09
        001 002 003 004 005 006  \a  \b  \t  \n
0000012

Octal 2-byte output with the characters:
Code:
$ od -oc < some_data
0000000 001001 002003 003005 004007 005011
        001 002 003 004 005 006  \a  \b  \t  \n
0000012

Octal output with the characters:
Code:
$ od -bc < some_data
0000000 001 002 003 004 005 006 007 010 011 012
        001 002 003 004 005 006  \a  \b  \t  \n
0000012

Then just use sed or something similar to remove/translate the characters.

EDIT: Added last example.
 

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