10-28-2010
Store highest filename from ls command to a variable
I am sure it has been answered in some form or the other in this forum but trust me I have spent last couple of hours looking for an answer but can't find it.
I want to do a very simple operation within my script.
Let's say I have 4 files with the names file1.log, file2.log, file3.log and file4.log. I want to do a listing of file*.log and store the highest name (in this case file4.log) in a variable. I have this in the script:
flist=$(ls file*.log)
which gives me a string or list in the format "file1.log file2.log file3.log file4.log.
How do I parse this string or file and store file4.log to a variable, say fname.
Thanks a lot in advance for the help.
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time(1) General Commands Manual time(1)
NAME
time - time a command
SYNOPSIS
command
utility [argument ...]
DESCRIPTION
When a specified command or utility completes execution, prints the elapsed time during the command or utility, the time spent in the sys-
tem, and the time spent executing the command or utility. Times are reported in seconds.
Execution time can depend on the performance of the memory in which the program is running.
The times are printed to standard error.
Note that the shell also has a keyword that times an entire pipeline if used anywhere in the pipeline. This action is different than the
command which times a particular command if used in a pipeline.
Options
recognizes the following options:
command The command to be executed and timed.
Writes the timing statistics to standard error.
utility The name of a utility to be invoked and timed. If the utility operand names any of the shell special built-in utilities,
the time results are undefined. See csh(1) and ksh(1) for information about special built-in utilities.
argument Any string that is an argument to the utility.
SEE ALSO
csh(1), ksh(1), sh(1), timex(1), times(2).
STANDARDS CONFORMANCE
time(1)