10-27-2010
GNU bash, version 3.2.25(1)-release (i686-redhat-linux-gnu)
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1. UNIX for Dummies Questions & Answers
Hi,
I have written a small shell script which logs into each oracle database on the server and displays whether it is in archivelog mode or not.. The script is as under:
#!/bin/bash
dblist=`ps -ef | grep smon | grep -v grep |cut -d'_' -f3`
for ohome in $dblist; do
sqlplus -s /nolog <<... (2 Replies)
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hi there
i write one awk script file in shell programing
the code is related to dd/mm/yy to month, day year format
but i get an error
please can anybody help me out in this problem ??????
i give my code here including error
awk `
# date-month -- convert mm/dd/yy to month day,... (2 Replies)
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Sorry typo found please ignore (0 Replies)
Discussion started by: jazz8146
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4. Shell Programming and Scripting
Hi,
I have the following table in MYSQL: (the structure looks broken in this forum but if you copy/paste it into notepad, it'll look right):
+----------------------------+-----------------------+------+-----+---------+----------------+
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5. Shell Programming and Scripting
I need help in the following script. I want to grep the sql errors insert into the error table and exit the shell script if there is any error, otherwise keep running the scripts.
Here is my script
#!/bin/csh -f
source .orapass
set user = $USER
set pass = $PASS
cd /opt/data/scripts
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6. Shell Programming and Scripting
hello everyone
i am beginner on shell scripting .and i am working on my project work on ad hoc network
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HI,
We are using two shell scripts, script.sh,env.sh, where env.sh will be called inside script.sh. The variable inside env.sh is used as $var in script.sh.But while running the script its not identifying that variable. Is there any permission needed to call a script inside another script.
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8. Shell Programming and Scripting
I am getting the following error while passing parameter to a shell script called within awk script. Any idea what's causing this issue and how to ix it ? Thanks
sh: -c: line 0: syntax error near unexpected token `newline'
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9. Shell Programming and Scripting
Hi All
when I execute from psql prompt, I get the result, when I try to automate
using a shell script, the query is not working
# `/usr/bin/psql -U postgres -d coba1 -c "select name from users where
"Date" > current_date - 30;"`
ERROR: column "Date" does not exist
LINE 1: select... (2 Replies)
Discussion started by: srilinux09
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LEARN ABOUT CENTOS
bashbug
BASHBUG(1) General Commands Manual BASHBUG(1)
NAME
bashbug - report a bug in bash
SYNOPSIS
bashbug [--version] [--help] [email-address]
DESCRIPTION
bashbug is a shell script to help the user compose and mail bug reports concerning bash in a standard format. bashbug invokes the editor
specified by the environment variable EDITOR on a temporary copy of the bug report format outline. The user must fill in the appropriate
fields and exit the editor. bashbug then mails the completed report to bug-bash@gnu.org, or email-address. If the report cannot be
mailed, it is saved in the file dead.bashbug in the invoking user's home directory.
The bug report format outline consists of several sections. The first section provides information about the machine, operating system,
the bash version, and the compilation environment. The second section should be filled in with a description of the bug. The third sec-
tion should be a description of how to reproduce the bug. The optional fourth section is for a proposed fix. Fixes are encouraged.
ENVIRONMENT
bashbug will utilize the following environment variables if they exist:
EDITOR Specifies the preferred editor. If EDITOR is not set, bashbug defaults to emacs.
HOME Directory in which the failed bug report is saved if the mail fails.
TMPDIR Directory in which to create temporary files and directories.
SEE ALSO
bash(1)
AUTHORS
Brian Fox, Free Software Foundation
bfox@gnu.org
Chet Ramey, Case Western Reserve University
chet@po.cwru.edu
GNU Bash-4.0 1998 July 30 BASHBUG(1)