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Shell Programming and Scripting
ksh: what does var=$(command) mean?
Post 302466529 by JamesByars on Tuesday 26th of October 2010 03:53:39 PM
10-26-2010
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Anyone knows why the following function does not work in ksh (it does in bash)?
var() # Displays var value; case insensitive
{
_var="$1"
if ; then
echo ${!_var}
else
_var=$(echo "$_var" | tr 'a-z' 'A-Z')
echo ${!_var}
fi
unset _var
}$ var home
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This works
#!/bin/ksh
FILE="file.txt"
dosumtin () {
date >> FILE
}
for i in {1..5}
do
dosumtin
done
cat $FILE
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LEARN ABOUT HPUX
zgrep
ZGREP(1) General Commands Manual ZGREP(1) NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)