Sponsored Content
Top Forums Shell Programming and Scripting Help parse comma separated list Post 302466394 by ctsgnb on Tuesday 26th of October 2010 10:21:14 AM
Old 10-26-2010
Code:
i=0
ls -t /HOME/Daily_*.txt | while read a
do
var[$i]=$a                                      or ${a##*/} if you want to get rid off the PATH
echo "var[$i] = ${var[$i]}"
let i++
done


Last edited by ctsgnb; 10-26-2010 at 11:42 AM..
 

9 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Unix shell script to parse the contents of comma-separated file

Dear All, I have a comma-separated file. 1. The first line of the file(header) should have 4 commas(5 fields). 2. The last line of the file should have 1 comma(2 fields). Pls help me in checking this condition in a shell script. And the number of lines between the first line and last... (11 Replies)
Discussion started by: KrishnaSaran
11 Replies

2. Shell Programming and Scripting

Parse apart strings of comma separated data with varying number of fields

I have a situation where I am reading a text file line-by-line. Those lines of data contain comma separated fields of data. However, each line can vary in the number of fields it can contain. What I need to do is parse apart each line and write each field of data found (left to right) into a file.... (7 Replies)
Discussion started by: 2reperry
7 Replies

3. Shell Programming and Scripting

Perl script to parse output and print it comma separated

I need to arrange output of SQL query into a comma separated format and I'm struggling with processing the output... The output is something like this: <Attribute1 name><x amount of white spaces><Atribute value> <Attribute2 name><x amount of white spaces><Atribute value> <Attribute3... (2 Replies)
Discussion started by: Juha
2 Replies

4. Shell Programming and Scripting

Output of command in comma separated list

Hi; I have an output of a particular command say $command fstl:r-x ajay:r-x how can i get this in comma separated list, eg: fstl:r-x,ajay:r-x Thnks; (4 Replies)
Discussion started by: ajaypadvi
4 Replies

5. Shell Programming and Scripting

Need Help - comma inside double quote in comma separated csv,

Hello there, I have a comma separated csv , and all the text field is wrapped by double quote. Issue is some text field contain comma as well inside double quote. so it is difficult to process. Input in the csv file is , 1,234,"abc,12,gh","GH234TY",34 I need output like below,... (8 Replies)
Discussion started by: Uttam Maji
8 Replies

6. UNIX for Dummies Questions & Answers

[solved] Comma separated values to space separated

Hi, I have a large number of files which are written as csv (comma-separated values). Does anyone know of simple sed/awk command do achieve this? Thanks! ---------- Post updated at 10:59 AM ---------- Previous update was at 10:54 AM ---------- Guess I asked this too soon. Found the... (0 Replies)
Discussion started by: lost.identity
0 Replies

7. Shell Programming and Scripting

awk to parse comma separated field and removing comma in between number and double quotes

Hi Experts, Please support I have below data in file in comma seperated, but 4th column is containing comma in between numbers, bcz of which when i tried to parse the file the column 6th value(5049641141) is being removed from the file and value(222.82) in column 5 becoming value of column6. ... (3 Replies)
Discussion started by: as7951
3 Replies

8. UNIX for Beginners Questions & Answers

How to extract fields from a CSV i.e comma separated where some of the fields having comma as value?

can anyone help me!!!! How to I parse the CSV file file name : abc.csv (csv file) The above file containing data like abv,sfs,,hju,',',jkk wff,fst,,rgr,',',rgr ere,edf,erg,',',rgr,rgr I have a requirement like i have to extract different field and assign them into different... (4 Replies)
Discussion started by: J.Jena
4 Replies

9. UNIX for Beginners Questions & Answers

Remove duplicates from comma separated list

Hi, I have following input file: niki niki niki1 niki niki2 niki,niki2 niki3 niki,niki3,niki niki4 niki4,blabla niki5 jkjkl niki6 niki60,niki6 I would like to delete lines with identical matches completely and remove the selfmatches in the other lines. ... (2 Replies)
Discussion started by: niki0211
2 Replies
NEWS(1) 							   USER COMMANDS							   NEWS(1)

NAME
news - display system news SYNOPSIS
news [-adDeflnpvxs] [[article1] [article2] ..] DESCRIPTION
The news command keeps you informed of news concerning the system. Each news item is contained in a separate file in the /var/lib/sysnews directory. Anyone having write permission to this directory can create a news file. If you run the news command without any flags, it displays every unread file in the /var/lib/sysnews directory. Each file is preceded by an appropriate header. To avoid reporting old news, the news command stores a currency time. The news command con- siders your currency time to be the date the $HOME/.news_time file was last modified. Each time you read the news, the modification time of this file changes to that of the reading. Only news item files posted after this time are considered unread. OPTIONS
-a, --all Display all news, also the already read news. -d, --datestamp Add a date stamp to each article name printed. this can only be used with the -nl flags. -D, --datefmt <fmt> Specify a date format, see the strftime(3) man page for more details. the default format is (%b %d %Y) -f, --newsdir <dir> Read news from an alternate newsdir. -l, --oneperline One article name per line. -n, --names Only show the names of news articles. -p, --page Pipe articles through $PAGER or more(1) if the $PAGER environment variable is not set. -s, --articles Reports the number of news articles. MAINTAINER OPTIONS
-e, --expire # Expire news older than # days. -x, --exclude a,b,c A comma separated list of articles which may not be expired. if a file named .noexpire exists in the /var/lib/sysnews direcory, filenames are read from it also. names in this file may be comma separated, and/or one per line. AUTHOR
Charles, <int@link.xs4all.nl> Linux 18 January 1995 NEWS(1)
All times are GMT -4. The time now is 01:53 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy