hello,
I am trying to parse an error returned by a command inside the if statement but it is just displays the full error instead and then stops.
if ; then
echo "no such package"
else
echo "similar version found will use pkgrm"
fi
the above code just displays
please let me know... (2 Replies)
:b:hi,
I have a script as given below:
pr_det="1"
if
then
awk ' BEGIN {printf("%23s","session")}' >> report.txt
awk ' BEGIN {printf "\n"} ' >> report.txt
else
awk ' BEGIN {printf("%55s","file_dsc")} ' >> report.txt
awk ' BEGIN {printf("%101s","no_recs")} '... (1 Reply)
year=`date '+%Y'`
month=`date '+%m'`
day=`date '+%d'`
day=`expr $day - 1`
case $month in
1 | 3 | 5 | 7 | 8 | 10 | 12);;
if($day =7 ); then
$day=6
fi
4 | 6 | 9 | 11);;
if ; then
$day=31
fi
2);;
if ; then
if ; then (2 Replies)
Hi ,
I am getting an error when I run the script for checking word "view" in a file . I am using if statement. like this
if
then
VW_VAR=` cat $TN.${ecmdate}.sql1 | grep -i view | awk '{print $3}' | cut -d '.' -f2 `
echo " VW_$VW_VAR "
sed -e... (16 Replies)
HI i am getting error while executing the given statement
for filename in `cat a/file.lst`
do
if then
echo "Exit Code Description :File $filename - is missing in Input Directory" >a.log
exit
else
count1=`awk 'END {print NR}' $filename`
echo "$count1">>a.log
count2=`awk 'END {print... (4 Replies)
hi,
When i try to run the code below, i get the following error
"ksh: syntax error: `(' unexpected"
i am not able to figure it out. Can anyone help me?
Code: (2 Replies)
Hi,
This is my script to catch any oracle errors.
In this, the $sqlerr returns
ORA-01017: invalid username/password; logon denied
when i specify wrong username/password
the if condition is failing. how can i resolve the issue.
the if statement gives error
sqloutput=`sqlplus -s -L... (1 Reply)
Hi
Can you please tell me what is wrong with this line:
if && ]; then
basically i want to check if x = 12 and F (Filename) end with 'g'. But it is throwing syntax error. (7 Replies)
Can anybody tell the correct way to use the following awk pattern check within an if statement?
When I run this command outside of the if statement
cat /tmp/test2.out | awk -v T=$TIME -v G=$GROUP -v C=$CDATE '$0 ~ T && $0 ~ G && $0 ~ C' | grep -i "Starting the group"
I get the following... (0 Replies)
hello all
im new to unix and when i use below script i get an error :
#! /bin/bash
Echo -e "enter the name of the file : \c"
read file_name
if
then
echo "$file_name found"
else
echo "$file_name not found"
fi
running the script i get below error :
$ ./hello (26 Replies)
Discussion started by: Ibrahims1
26 Replies
LEARN ABOUT SUSE
xzegrep
XZGREP(1) XZ Utils XZGREP(1)NAME
xzgrep - search compressed files for a regular expression
SYNOPSIS
xzgrep [grep_options] [-e] pattern file...
xzegrep ...
xzfgrep ...
lzgrep ...
lzegrep ...
lzfgrep ...
DESCRIPTION
xzgrep invokes grep(1) on files which may be either uncompressed or compressed with xz(1), lzma(1), gzip(1), or bzip2(1). All options
specified are passed directly to grep(1).
If no file is specified, then the standard input is decompressed if necessary and fed to grep(1). When reading from standard input,
gzip(1) and bzip2(1) compressed files are not supported.
If xzgrep is invoked as xzegrep or xzfgrep then egrep(1) or fgrep(1) is used instead of grep(1). The same applies to names lzgrep, lze-
grep, and lzfgrep, which are provided for backward compatibility with LZMA Utils.
ENVIRONMENT
GREP If the GREP environment variable is set, xzgrep uses it instead of grep(1), egrep(1), or fgrep(1).
SEE ALSO grep(1), xz(1), gzip(1), bzip2(1), zgrep(1)Tukaani 2009-07-05 XZGREP(1)