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Full Discussion: Getting filenames from a directory in single line
Top Forums Shell Programming and Scripting Getting filenames from a directory in single line Post 302459500 by agama on Monday 4th of October 2010 09:28:00 PM
Old 10-04-2010
In awk, the print command will always add a newline, use printf() instead.

Code:
ls | awk ' { printf( "%s ", $NF ) } END { printf( "\n" ); }'

Also, you can 'cut' away the path with a simple sub() function call in the awk rather than adding the extra overhead required by using cut.

Code:
sub( ".*/", "", $NF );

Last edited by agama; 10-04-2010 at 10:29 PM.. Reason: typo
 

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LEARN ABOUT REDHAT

igawk

IGAWK(1)							 Utility Commands							  IGAWK(1)

NAME

       igawk - gawk with include files

SYNOPSIS

       igawk [ all gawk options ] -f program-file [ -- ] file ...
       igawk [ all gawk options ] [ -- ] program-text file ...

DESCRIPTION

       Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1).

       AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like

	      @include getopt.awk

       in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path.

OPTIONS

       See gawk(1) for a full description of the AWK language and the options that gawk supports.

EXAMPLES

       cat << EOF > test.awk
       @include getopt.awk

       BEGIN {
	    while (getopt(ARGC, ARGV, "am:q") != -1)
		 ...
       }
       EOF

       igawk -f test.awk

SEE ALSO

       gawk(1)

       Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995.

AUTHOR

       Arnold Robbins (arnold@skeeve.com).

Free Software Foundation					    Nov 3 1999								  IGAWK(1)
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