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Top Forums Shell Programming and Scripting Help with simple grep command Post 302458792 by puttster on Friday 1st of October 2010 10:29:24 PM
Old 10-01-2010
say $a contains 5 rows of random digits, if I do grep "therandomdigits" $a... It only shows 1 line of digits, but If I do grep -c "therandomdigits" $a it shows 5 as output meaning 5 lines of output correct?

---------- Post updated at 09:23 PM ---------- Previous update was at 09:22 PM ----------

Quote:
Originally Posted by durden_tyler
grep -c prints the count of matching lines per file. So, if

Code:
grep something file

displays a single line, then

Code:
grep -c something file

will print 1.

tyler_durden
If $anything is a variable that is initialized as # shouldnt grep display all lines that contain #?
For my code, it only displays one line but counts 6 or so.

---------- Post updated at 09:29 PM ---------- Previous update was at 09:23 PM ----------

Better example

s=#
$a contains

stanle#y hey
tc#p ss#h
udp tcp
PDB CDB

grep -c "$s" $a =

2

but grep "$s" $a =

stanle#y hey
 

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ZGREP(1)                                                      General Commands Manual                                                     ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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