say $a contains 5 rows of random digits, if I do grep "therandomdigits" $a... It only shows 1 line of digits, but If I do grep -c "therandomdigits" $a it shows 5 as output meaning 5 lines of output correct?
---------- Post updated at 09:23 PM ---------- Previous update was at 09:22 PM ----------
Quote:
Originally Posted by durden_tyler
grep -c prints the count of matching lines per file. So, if
displays a single line, then
will print 1.
tyler_durden
If $anything is a variable that is initialized as # shouldnt grep display all lines that contain #?
For my code, it only displays one line but counts 6 or so.
---------- Post updated at 09:29 PM ---------- Previous update was at 09:23 PM ----------
Hi all,
My boss wants me to find out how often e-m users are accessing their account:confused:. The mail server keeps log of all logins. I want to use grep the 'usernames', but it should come out the moment it first encounters the username in the log. Can I do that? I want to avoid 10+ greps... (2 Replies)
I have seen this used several times but not really sure of what it actually does. I am confused with the second grep as the argument to the first.
some commands | grep -v grep | some other commands
Can anyone provide an explanation?
Thanks, (5 Replies)
I have 3 files in directory mydir named as follows, I run the sequence of commands shown below and I have questions at the result.
File names are:
ABC_GP0
ABC_GP0.ctl
ABC_GPX
Commands and results:
$ ls /mydir/ | grep *
<-- (q1) I get nothing - OK
$ ls /mydir/ | grep... (5 Replies)
How come grep testfile1 won't find anything in testfile1 (even though the characters sd are there in great quantity), but grep '' testfile1 will find plenty?
Do the single quotes prevent the shell from interpreting the testfile1 is interpreted as: grep *test whether or not characters sd exist*... (5 Replies)
I tried searching for answers but didn't find any.
When I grep a file results read
4.2.2.2
4.4.4.2
4.5.6.7
But I just want to select each result individually. For Example I want to be able to say
variable1="first grep result"
variable2="second grep result"
variable3="third grep... (8 Replies)
Hi, On the log Netscape log, I need to grep for 500 error. I am doing that but I also get 1500 in that same log.
cat access |grep "500"
Results:
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This not what I need... Please advice. (4 Replies)
This should be so easy...
I want to find all the apps in /Applications that start with the lower case i (e.g. iTunes.app, iSync.app, iCal.app) They should all have the .app extension. I've tried:
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ls /Applications/i*.app
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I'm trying to write a simple script to identify every user who tried to “sudo” on the system. I have the first portion down to grep the log file
grep “sudo” /var/log/secure.
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Hello,
I am trying to grep my log files for ORA errors, except ORA-00001.
I have tried:
grep 'ORA*!(-00001)' *.log
but it is not working.
Any help will be much appreciated.
Thank you. (5 Replies)
I hope someone can help me.
I have a folder e.g. /opt/application
Under that are many sub folders e.g.
Folder1
Folder2
Folder3
Folder4
Folder5
Folder6
etc
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I need to run a grep that will start at... (3 Replies)
Discussion started by: gunnahafta
3 Replies
LEARN ABOUT X11R4
zgrep
ZGREP(1) General Commands Manual ZGREP(1)NAME
zgrep - search possibly compressed files for a regular expression
SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename...
DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code:
(-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the
standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep.
If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.
EXIT CODE
2 - An option that is not supported was specified.
AUTHOR
Charles Levert (charles@comm.polymtl.ca)
SEE ALSO grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)ZGREP(1)