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Full Discussion: Error in if statement
Top Forums Shell Programming and Scripting Error in if statement Post 302457482 by frans on Tuesday 28th of September 2010 06:25:23 AM
Old 09-28-2010
A proper indentation and syntax coloration helps a lot
bash code:
  1. #!/bin/bash
  2. set -x
  3. #
  4. grep -  data01awk.log
  5. if [ $? -eq 0 ]
  6. then
  7.    if [ `data01stale.log | wc -l` -eq 1 ]
  8.    then
  9.       awk '$1 $2 $3 == "---" { exit 1 }' data01stale.log
  10.       #awk '$2 $3 $4 == "---" { exit 1 }' data01stale.log}
  11.       if [ $? -ne 0 ]
  12.       then
  13.          echo "Found NFS issues on data01"
  14.          u=$(awk '{ print $5 }' data01stale.log)
  15.          printf "                 NFS issues on data01                                                \n"
  16.          #grep -i $u data01Out.log
  17.          echo -e "[root@data01 ]# df -hP | grep -i $u \n"
  18.          #df -hP | grep -i $u
  19.          echo " "
  20.       fi
  21.    else
  22.       echo "Found Multiple NFS issues on data01"
  23.       for u in `(data01stale.log |  awk '{print $5}')`
  24.       do
  25.          echo -e "[root@data01 ]# df -hP | grep -i $u \n"
  26.          df -hP | grep -i $u
  27.          echo " "
  28.       fi
  29.    else
  30.       printf "                      NO  NFS issues on ausomxdta01                                       \n"
  31.       echo -e "[root@data01 ${UUID}]# df -hP \n"
  32.       df -hP
  33.       exit
  34.    fi
  35. done
Line 28 You have an unexpected fi statement before the end of for .. in .. do .. done
 

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