Sponsored Content
Top Forums UNIX for Dummies Questions & Answers Complete command list/argument using ps Post 302456043 by jlliagre on Thursday 23rd of September 2010 05:06:14 AM
Old 09-23-2010
This is OS dependant.
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

command find returned bash: /usr/bin/find: Argument list too long

Hello, I create a file touch 1201093003 fichcomp and inside a repertory (which hava a lot of files) I want to list all files created before this file : find *.* \! -maxdepth 1 - newer fichcomp but this command returned bash: /usr/bin/find: Argument list too long but i make a filter all... (1 Reply)
Discussion started by: yacsil
1 Replies

2. Shell Programming and Scripting

assign a command line argument and a unix command to awk variables

Hi , I have a piece of code ...wherein I need to assign the following ... 1) A command line argument to a variable e.g origCount=ARGV 2) A unix command to a variable e.g result=`wc -l testFile.txt` in my awk shell script When I do this : print "origCount" origCount --> I get the... (0 Replies)
Discussion started by: sweta_doshi
0 Replies

3. Shell Programming and Scripting

How Get Complete Date in List of file

Hi, I am unable to get the complete date format in ls command. I need to list file with complete date format in home directory. If I give 2007/01/01 then i should get all the log files below that particular date. Pls help me (2 Replies)
Discussion started by: Satyak
2 Replies

4. Shell Programming and Scripting

Cannot compare argument in if statement in csh/grep command if argument starts with “-“

If ($argv == “-debug”) then Echo “in loop” Endif But this is not working. If I modify this code and remove “-“, then it works. Similarly I am getting problem using grep command also Grep “-debug” Filename Can someone please help me on how to resolve these... (1 Reply)
Discussion started by: sarbjit
1 Replies

5. UNIX for Dummies Questions & Answers

Argument list too long for Sed command

Hi guys Following command results in sed -i 's/#/\\#/g' /home/test/sqlstents* -bash: /bin/sed: Argument list too long Please help me solve it.. is there any other way i can do this?.. thanks (4 Replies)
Discussion started by: depakjan
4 Replies

6. Shell Programming and Scripting

Argument list too long for date command

Dear Friends, The following script processes a 14508 lines log file. #!/bin/sh while read line do d=`sed 's/* - * \*\/*\/* *\)\] .*/\1/' | tr '/' ' ' | sed 's/\(*\):\(*\)/\1 \2/'` y=`date -d "${d}" "+%Y%m%d%H%M%S"` echo "${y}" done While running the above script, I am... (4 Replies)
Discussion started by: tamil.pamaran
4 Replies

7. Solaris

Show complete command on command line when we use 'ps'

Hi, When I query using ps -ef, the complete command is not displayed and is truncated. Can you please tell me a method to resolve this ? I have tried the below. ps -ef | cat ps -ef | grep imp >/tmp/t1.txt /usr/ucb/ps -auxw pargs <pid> /usr/ucb/ps -aefyl | grep imp Thanks (11 Replies)
Discussion started by: mk1216
11 Replies

8. Shell Programming and Scripting

In Shell Script Does Second Command Wait For First Command To Complete

Hi All, I have a question related to Shell scripting. In my shell script, I have following two commands in sequence: sed 's/^/grep "^120" /g' $ORIGCHARGEDAMTLIST|sed "s;$;| cut -f$FIELD_NO1 -d '|' | awk '{ sum+=\$1} END {printf (\"%0.2f\\\n\", sum/100)}' >$TEMPFILE mv $TEMPFILE $ORIGFILE... (3 Replies)
Discussion started by: angshuman
3 Replies

9. Shell Programming and Scripting

Argument list too long

Hi Team, Here's the situation. I have approximately 300000 to 500000 jpg files in /appl/abcd/work_dir mv /appl/abcd/work_dir /appl/abcd/process_dir The above move command will work if the jpg files count is close to 50000 (not sure). If the count is less this mv command holds good. But if... (14 Replies)
Discussion started by: kmanivan82
14 Replies

10. Shell Programming and Scripting

Specifying a list name as argument and using that list in script.

Is there a way I can specify the name of a list as an argument to a shell script and then use the values of that list name in the script? I need to do this WITHOUT using case statements. Something like this: check.sh list1 #!/bin/bash list1="www.amazon.com www.google.com"... (9 Replies)
Discussion started by: gctaylor
9 Replies
prev(1) 						      General Commands Manual							   prev(1)

NAME
prev - show the previous message (only available within the message handling system, mh) SYNOPSIS
prev [+folder] [-[no]header] [-help] [-showproc program] [-noshowproc] [options to showproc] OPTIONS
Displays a one-line header before the message. The header consists of the name of the folder and the message number. This is the default behavior. It can be suppressed with the -noheader option. Prints a list of the valid options to this command. Specifies an alternative program to list messages. The default is to use the program defined by the showproc: entry in the file. As with show, you can give options to the showproc program at the command line. These are passed directly to showproc by prev. The defaults for this command are: +folder defaults to the current folder -header DESCRIPTION
The prev command displays the previous message in the current folder. The previous message is the one before the current message in the folder. The message that is shown becomes the current message. You can specify a folder other than the current folder by using the +folder argument. If you specify a folder, that becomes the current folder. RESTRICTIONS
The prev command is really a link to the show program. As a result, if you make a link to prev and that link is not called prev, your link will act like show instead. To avoid this, add a profile-entry for the link to your MH profile and add the argument prev to the entry. PROFILE COMPONENTS
Path: To determine your Mail directory showproc: Program to show the message EXAMPLES
The command in the following example displays the previous message in the folder +copylog: $ prev +copylog FILES
The user profile. SEE ALSO
show(1), next(1) prev(1)
All times are GMT -4. The time now is 12:54 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy