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Top Forums Programming How to right pad with zeros using sprintf? Post 302455400 by shamrock on Tuesday 21st of September 2010 01:22:44 PM
Old 09-21-2010
Quote:
Originally Posted by emitrax
I'm not sure I understood how it works.

The first character conversion prints whatever the buffer variable contains.
The second should print "0" padded with 18 zeros right?
It would be right padded with 19 zeros.
Quote:
Originally Posted by emitrax
Wouldn't that produce an output as big as strlen(buffer) + 19?
So you need to right pad zeros all the empty slots of buffer...and did you look at all at the solution posted by jim mcnanamara. It has exactly what you want...
Code:
s = sizeof buf;
l = strlen(buf);
d = s - l;
printf("%s%0*s\n", buf, d>0 ? d : 0, d>0 ? "0" : "");

 

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NE_BUFFER_DESTROY(3)						neon API reference					      NE_BUFFER_DESTROY(3)

NAME
ne_buffer_destroy, ne_buffer_finish - destroy a buffer object SYNOPSIS
#include <ne_string.h> void ne_buffer_destroy (ne_buffer *buf); char *ne_buffer_finish (ne_buffer *buf); DESCRIPTION
ne_buffer_destroy frees all memory associated with the buffer. ne_buffer_finish frees the buffer structure, but not the actual string stored in the buffer, which is returned and must be free()d by the caller. Any use of the buffer object after calling either of these functions gives undefined behaviour. RETURN VALUE
ne_buffer_finish returns the malloc-allocated string stored in the buffer. EXAMPLES
An example use of ne_buffer_finish; the duplicate function returns a string made up of n copies of str: static char *duplicate(int n, const char *str) { ne_buffer *buf = ne_buffer_create(); while (n--) { ne_buffer_zappend(buf, str); } return ne_buffer_finish(buf); } SEE ALSO
ne_buffer(3), ne_buffer_create(3), ne_buffer_zappend(3) AUTHOR
Joe Orton <neon@webdav.org>. neon 0.23.5 8 October 2002 NE_BUFFER_DESTROY(3)
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