awk command in script gives error while same awk command at prompt runs fine: Why?
Hello all,
Here is what my bash script does: sums number columns, saves the tot in new column, outputs if tot >= threshold val:
When I call the script at the prompt, I get an error:
When I run the awk command alone at the prompt, I obtain the results I want
Is there any way around what seems to me an attractable error?
Thanks.
Just in case you need it, the datafile (xyz.38) look like this:
Last edited by radoulov; 09-20-2010 at 06:14 PM..
Reason: Code tags, please!
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Discussion started by: boxstep
7 Replies
LEARN ABOUT MOJAVE
ualarm
UALARM(3) BSD Library Functions Manual UALARM(3)NAME
ualarm -- schedule signal after specified time
LIBRARY
Standard C Library (libc, -lc)
SYNOPSIS
#include <unistd.h>
useconds_t
ualarm(useconds_t useconds, useconds_t interval);
DESCRIPTION
This is a simplified interface to setitimer(2).
The ualarm() function waits a count of useconds before asserting the terminating signal SIGALRM. System activity or time used in processing
the call may cause a slight delay.
If the interval argument is non-zero, the SIGALRM signal will be sent to the process every interval microseconds after the timer expires
(e.g., after useconds number of microseconds have passed).
Due to a setitimer(2) restriction, the maximum number of useconds and interval is limited to 100,000,000,000,000 (in case this value fits in
the unsigned integer).
RETURN VALUES
When the signal has successfully been caught, ualarm() returns the amount of time left on the clock.
NOTES
A microsecond is 0.000001 seconds.
SEE ALSO getitimer(2), setitimer(2), sigpause(2), sigvec(2), alarm(3), signal(3), sleep(3), usleep(3)HISTORY
The ualarm() function appeared in 4.3BSD.
BSD April 19, 1994 BSD