Hi
I have a input file in the format
ABC,111,2008Q2, 49K
ABC,111,2008Q3, 0K
ABC,111,2008Q4, 0K
ABC,222,2008Q2, 49K
ABC,222,2008Q3, 0K
ABC,222,2008Q4, 0K
XYZ,111,2008Q2, 49K
XYZ,111,2008Q3, 0K
XYZ,111,2008Q4, 0K
XYZ,222,2008Q2, 49K
XYZ,222,2008Q3, 0K
XYZ,222,2008Q4, 0K
The output file... (3 Replies)
Hi guys
Could anyone advise me how to convert my rows into columns from a file
My file would be similar to this:
A11 A12 A13 A14 A15 ... A1n
A21 A22 A23
A31
A41
A51
...
Am1 Am2 Am3 Am4 Am5 ... Amn
The number of rows is not the same to the number of columns
Thanks in advance (2 Replies)
hi,
Apologies if this has been covered.
I have requirement where i have to convert a single column into multiple column.
My data will be like this -
2
3
4
5
6
Output required -
2 3 4 5 6 (1 Reply)
Hi Gurus,
How to convert rows in to columns using linux shell scripting
Input is like (sample.txt)
ABC
DEF
GHI
JKL
MNO
PQR
STU
VWX
YZA
BCD
output should be (sampleoutput.csv)
ABC,DEF,GHI,JKL,MNO
PQR,STU,VWX,YZA,BCD (2 Replies)
Hi Everyone,
Could someone shed some lights on how to convert the records in rows form into column basis.
172.29.59.12
IBM,8255-E8B
102691P
8
65536 MB
6100-04-11-1140
172.29.59.15
IBM,8255-E8B
102698P
4
45056 MB
6100-04-11-1140
IP SYS MODEL ... (6 Replies)
I am looking to print the data in columns and after every 3 words it should be a new row.
cat example.out | awk 'END { for (i = 0; ++i < m;) print _;print _ }{ _ = _ x ? _ OFS $1 : $1}' m=1| grep -i INNER
I am looking to print in a new line after every 3 words.
... (2 Replies)
hi folks,
I have a sample data like what is shown below:
1,ID=1000
1,Org=CedarparkHospital
1,cn=john
1,sn=doe
1,uid=User001
2,uid=User002
2,ID=2000
2,cn=steve
2,sn=jobs
2,Org=Providence
I would like to convert it into the below format:
1,1000,CedarparkHospital,john,doe,User001... (11 Replies)
Discussion started by: vskr72
11 Replies
LEARN ABOUT DEBIAN
load_dat_font
load_dat_font(3alleg4) Allegro manual load_dat_font(3alleg4)NAME
load_dat_font - Loads a FONT from an Allegro datafile.
SYNOPSIS
#include <allegro.h>
FONT *load_dat_font(const char *filename, RGB *pal, void *param)
DESCRIPTION
Loads a FONT from an Allegro datafile. You can set param parameter to point to an array that holds two strings that identify the font and
the palette in the datafile by name. The first string in this list is the name of the font. You can pass NULL here to just load the first
font found in the datafile. The second string can be used to specify the name of the palette associated with the font. This is only
returned if the pal parameter is not NULL. If you pass NULL for the name of the palette, the last palette found before the font was found
is returned. You can also pass NULL for param, which is treated as if you had passed NULL for both strings separately. In this case, the
function will simply load the first font it finds from the datafile and the palette that precedes it.
For example, suppose you have a datafile named `fonts.dat' with the following contents:
FONT FONT_1_DATA
FONT FONT_2_DATA
FONT FONT_3_DATA
PAL FONT_1_PALETTE
PAL FONT_2_PALETTE
Then the following code will load FONT_1_DATA as a FONT and return FONT_1_PALETTE as the palette:
FONT *f;
PALETTE pal;
char *names[] = { "FONT_1_DATA", "FONT_1_PALETTE" }
f = load_dat_font("fonts.dat", pal, names);
If instead you want to load the second font, FONT_2, from the datafile, you would use:
FONT *f;
PALETTE pal;
char *names[] = { "FONT_2_DATA", "FONT_2_PALETTE" }
f = load_dat_font("fonts.dat", pal, names);
If you want to load the third font, but not bother with a palette, use:
FONT *f;
char *names[] = { "FONT_3_DATA", NULL }
f = load_dat_font("fonts.dat", NULL, names);
RETURN VALUE
Returns a pointer to the font or NULL on error. Remember that you are responsible for destroying the font when you are finished with it to
avoid memory leaks.
SEE ALSO register_font_file_type(3alleg4), load_font(3alleg4)Allegro version 4.4.2 load_dat_font(3alleg4)