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Shell Programming and Scripting
Result of the grep is not storred correctly into the variable
Post 302451683 by renjithv on Tuesday 7th of September 2010 06:34:43 PM
09-07-2010
Result of the grep is not storred correctly into the variable
I am facing a problem while storring the grep results into a variable. I need to count the occurence of the pattern \, in a file and store that in a variable. I have given the below command
p=`grep -c '\\,' filename`
But while echoing the variable, i am getting the total number of lines in the file instead of the count of lines having pattern \, . If i give grep directly i am getting the correct result. Please help
$grep -c '\\,' filename
1
$p=`grep -c '\\,' filename`
$echo $p
29
Regards
Renjith
p=`grep -c '\\,' filename`
But while echoing the variable, i am getting the total number of lines in the file instead of the count of lines having pattern \, . If i give grep directly i am getting the correct result. Please help
$grep -c '\\,' filename
1
$p=`grep -c '\\,' filename`
$echo $p
29
Regards
Renjith
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LEARN ABOUT PLAN9
zgrep
ZGREP(1) General Commands Manual ZGREP(1) NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)