Sponsored Content
Top Forums Shell Programming and Scripting expr command to extract words Post 302451119 by fpmurphy on Sunday 5th of September 2010 09:23:03 PM
Old 09-05-2010
Here is an example of how to do what you want to do:
Code:
$ A="foo=bar"
$ echo $A
foo=bar
$ expr "$A" : '\(.*\)=.*'
foo

From IEEE Std 1003.1:2008
Quote:
The ':' matching operator shall compare the string resulting from the evaluation of expr1 with the regular expression pattern resulting from the evaluation of expr2. Regular expression syntax shall be that defined in the Base Definitions volume of IEEE Std 1003.1-2001, Section 9.3, Basic Regular Expressions, except that all patterns are anchored to the beginning of the string (that is, only sequences starting at the first character of a string are matched by the regular expression) and, therefore, it is unspecified whether '^' is a special character in that context. Usually, the matching operator shall return a string representing the number of characters matched ( '0' on failure). Alternatively, if the pattern contains at least one regular expression subexpression "[\(...\)]", the string corresponding to "\1" shall be returned.
This User Gave Thanks to fpmurphy For This Post:
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

expr command

I am looking for the correct syntax on the expr command in UNIX. I have a script that I am building at the moment. the script is creating file1 that is an actual .sql file that is going inside the oracle database to get some information in there. It take that information, puts it inside another... (2 Replies)
Discussion started by: wolf
2 Replies

2. UNIX for Advanced & Expert Users

How to extract two words at the same time.

Hi, Can anyone please let me know, how to extract two lines at the same time. In specific,I have a file containing list of devices, such as router1 and switch2 below. I want to get all the lines which has "#" and all the lines which has "down" router1#sh ip int br Interface ... (6 Replies)
Discussion started by: Aejaz
6 Replies

3. UNIX for Dummies Questions & Answers

using the expr command

Hi friends how can i execute expr $va1 * $var2 provided i m not supposed to use '/' also the nglob variable is turned off. (4 Replies)
Discussion started by: ashishj
4 Replies

4. Shell Programming and Scripting

expr command

Hi Can anyone explain me the usage of this command and the arguments used here and what will be the expected output : v_num=`expr nav_d_20100204_1759 : '*\(*\)'` what will be the value returned in v_num. Thanks in Advance!!! Regards Naveen Purbia (3 Replies)
Discussion started by: trying_myluck
3 Replies

5. Shell Programming and Scripting

Usage of grep command to extract only the words.

Dear Folks, I am a newbee to UNIX. I want to extract the SQLSTATE from a log file. For example the log file content is SQL0010N The string constant beginning with "' from table1 a, table 2" does not have an ending string delimiter. SQLSTATE=42603 when I give the the command as ... (4 Replies)
Discussion started by: dinesh1985
4 Replies

6. UNIX for Dummies Questions & Answers

Extract words to new file

Hi there, Unix Gurus Working with big listings of english sentences for my pupils, of the type: 1. If the boss's son had been , someone would have asked for money by now. 2. Look, I haven't a crime, so why can't you let me go? .... I wondered how to extract the words between brackets in... (7 Replies)
Discussion started by: eldeingles
7 Replies

7. Shell Programming and Scripting

expr command help

I'm trying to check if a variable'd string is only one character and use that in an if statement the only way I could find is: $expr "${var}" : . # expr STRING : regrep where the "." is the grep wildcard for any single character. Whats wrong with my code here and is there a... (3 Replies)
Discussion started by: Tewg
3 Replies

8. Shell Programming and Scripting

Extract words from a pipe

Hello, Currently, I have this output from my application : ------------------------------------------------- Log viewer/Tmp1 (Jun 29 2011 09:48) ------------------------------------------------- BlalbalbaBlalbalba..Blalbalba..Blalbalba..Blalbalba..Blalbalba..Blalbalba..Blalbalba....... (3 Replies)
Discussion started by: acidoangel
3 Replies

9. Shell Programming and Scripting

Extract words before and after a certain word.

I have a sample text file with file name: sample.txt The text file has the following text. this is an example text where we have to extract certain words before and after certain word these words can be used later to get more information I want to extract n (a constant) words before and... (2 Replies)
Discussion started by: shoaibjameel123
2 Replies

10. UNIX for Beginners Questions & Answers

Extract Bracketed Words

Hi there, Unixers I need to extract ALL the words from a text which aresurrounded by square brackets. I am using this piece of code sed 's/.*\.*/\1/g' inputfile > outputfile but I only get one word for every paragraph, why? Please use CODE tags as required by forum rules! (7 Replies)
Discussion started by: eldeingles
7 Replies
EXPR(1) 						    BSD General Commands Manual 						   EXPR(1)

NAME
expr -- evaluate expression SYNOPSIS
expr expression DESCRIPTION
The expr utility evaluates expression and writes the result on standard output. All operators are separate arguments to the expr utility. Characters special to the command interpreter must be escaped. Operators are listed below in order of increasing precedence. Operators with equal precedence are grouped within { } symbols. expr1 | expr2 Returns the evaluation of expr1 if it is neither an empty string nor zero; otherwise, returns the evaluation of expr2. expr1 & expr2 Returns the evaluation of expr1 if neither expression evaluates to an empty string or zero; otherwise, returns zero. expr1 {=, >, >=, <, <=, !=} expr2 Returns the results of integer comparison if both arguments are integers; otherwise, returns the results of string comparison using the locale-specific collation sequence. The result of each comparison is 1 if the specified relation is true, or 0 if the relation is false. expr1 {+, -} expr2 Returns the results of addition or subtraction of integer-valued arguments. expr1 {*, /, %} expr2 Returns the results of multiplication, integer division, or remainder of integer-valued arguments. expr1 : expr2 The ``:'' operator matches expr1 against expr2, which must be a regular expression. The regular expression is anchored to the begin- ning of the string with an implicit ``^''. expr expects "basic" regular expressions, see re_format(7) for more information on regu- lar expressions. If the match succeeds and the pattern contains at least one regular expression subexpression ``(...)'', the string corresponding to ``1'' is returned; otherwise the matching operator returns the number of characters matched. If the match fails and the pattern contains a regular expression subexpression the null string is returned; otherwise 0. Parentheses are used for grouping in the usual manner. EXAMPLES
1. The following example adds one to the variable a. a=`expr $a + 1` 2. The following example returns the filename portion of a pathname stored in variable a. The // characters act to eliminate ambiguity with the division operator. expr //$a : '.*/(.*)' 3. The following example returns the number of characters in variable a. expr $a : '.*' DIAGNOSTICS
The expr utility exits with one of the following values: 0 the expression is neither an empty string nor 0. 1 the expression is an empty string or 0. 2 the expression is invalid. STANDARDS
The expr utility conforms to IEEE Std 1003.2 (``POSIX.2''). BSD
July 3, 1993 BSD
All times are GMT -4. The time now is 08:54 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy