09-03-2010
Thanks for replying guys
bartus11
When using awk -F\, -vOFS=\, '{$NF=$NF-1}1' file
I get my file but the last column shows the value -1
What I want is that last column to be removed, not to show any other value
Scottn
I don't need to store all the last comma-separated files in one variable.
What I was trying to do as a second approach was to identify the position of that last column and store that single position number in a variable so I could use cut to remove it
What else can I use to get that position number?
Thanks
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PR(1) General Commands Manual PR(1)
NAME
pr - print file
SYNOPSIS
pr [ option ] ... [ file ] ...
DESCRIPTION
Pr produces a printed listing of one or more files. The output is separated into pages headed by a date, the name of the file or a speci-
fied header, and the page number. If there are no file arguments, pr prints its standard input.
Options apply to all following files but may be reset between files:
-n Produce n-column output.
+n Begin printing with page n.
-h Take the next argument as a page header.
-wn For purposes of multi-column output, take the width of the page to be n characters instead of the default 72.
-ln Take the length of the page to be n lines instead of the default 66.
-t Do not print the 5-line header or the 5-line trailer normally supplied for each page.
-sc Separate columns by the single character c instead of by the appropriate amount of white space. A missing c is taken to be a tab.
-m Print all files simultaneously, each in one column,
Inter-terminal messages via write(1) are forbidden during a pr.
FILES
/dev/tty? to suspend messages.
SEE ALSO
cat(1)
DIAGNOSTICS
There are no diagnostics when pr is printing on a terminal.
PR(1)