Ive got a file with words and also numbers.
Bla BLA
10 10
11 29
12 89
13 35
And i need to change "10,29,89,25" and also remove anything that contains actually words... (4 Replies)
I can print a line with an expression using this:
awk '/regex/'
I can print the line immediately before an expression using this:
awk '/regex/{print x};{x=$0}'
How do I print the line immediately before and then the line with the expression? (2 Replies)
in shell scripting there is extensive usage of
i> regular expression
ii>sed
iii>awk
can anyone tell me the suitable contexts ...i mean which one is suitable for what kind of operation.
like the reg-exp and sed seems to be doing the same job..i.e pattern matching (1 Reply)
Hi, I need
to make some extraction . with the following input to get the right output.
input: /etc/exp/home/bin ====> output: exp
and
input: aex1234 ===> output: ex
Thanks for your help, (4 Replies)
Hi Experts,
Can you please help me out for the below scenario,
I have a variable length file with the fixed number of columns, in which the fields are delimited by pipe symbol (|). From that file I have to extract the lines which has the following scenario,
The field1 in a... (1 Reply)
Hello world,
I was wondering if there is a nicer way to write the following code (in AWK):
awk '
FNR==NR&&$1~/^m$/{tok1=1}
FNR==NR&&$1~/^m10$/{tok1=1}
' my_file
In fact, it looks for m2, m4, m6, m8 and m10 and then return a positive flag. The problem is how to define 10 thanks... (3 Replies)
Hi Experts,
I am adding a column of numbers with awk , however not getting correct output:
# awk '{sum+=$1} END {print sum}' datafile
2.15291e+06
How can I getthe output like : 2152910
Thank you..
# awk '{sum+=$1} END {print sum}' datafile
2.15079e+06 (3 Replies)
Hello,
I have big files which I wanna filter them based on first column.
first column should be one of these strings: chr2L || chr2R || chr3L || chr3R || chr4 || chrX
and something like chr2Lh or chrY or chrM3L is not accepted.
I used the following command:
awk '{ if ($1=="chr2L" ||... (5 Replies)
Hi Unix Gurus,
yesterday I asked a question and got answer, it works fine.
I have one more thing need to help
in the code
awk '{print substr($0,1,3)"xxx"substr($0,7)}' file
If I have 50 charactor's need to be replaced, is there any easy way to use reg exp or I have to input 50 XXXXx......... (12 Replies)
Discussion started by: ken6503
12 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)