Sponsored Content
Special Forums Windows & DOS: Issues & Discussions Auto download - filename UCC-YYYYMMDD.zip format. Post 302446021 by Corona688 on Tuesday 17th of August 2010 11:44:59 AM
Old 08-17-2010
Quote:
Originally Posted by methyl
Generating YYYYMMDD depends on the reply to the MSDOS "date" command.
Thank you for pointing out that its output differs by region! Actually though, it depends on the %date% builtin, which is not a command. </nitpick>
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

get yesterday date in yyyymmdd format

I would like to know how I could get a yesterday date in yyyymmdd e.g. today is 20011109, and I would like to get 20011108. Thank you!:confused: (2 Replies)
Discussion started by: hk_newbie
2 Replies

2. HP-UX

How can i get the yesterday's date in YYYYMMDD format

How can i get the yesterday's date in YYYYMMDD format??? (4 Replies)
Discussion started by: prasadsr
4 Replies

3. Shell Programming and Scripting

get yesterday in yyyymmdd format

how can i get yesterday in yyyymmdd format? :confused: (13 Replies)
Discussion started by: aaron_fong
13 Replies

4. UNIX for Dummies Questions & Answers

Format date from MM/DD/YYYY to YYYYMMDD

I have a file with some date columns in MM/DD/YYYY format: SMPBR|DUP-DO NOT USE|NEW YORK||16105|BA5270715|6/6/2007 |MWERNER|109||||JOHN||SMITH|MD|72211118||||||74559|21 WILMINGTON RD||D|11/6/2003|SL# MD CONTACT-LIZ RICHARDS|||0|Y|N||1411458| And I want to convert the date format to: ... (5 Replies)
Discussion started by: ChicagoBlues
5 Replies

5. Shell Programming and Scripting

Find the next day from 20100303 (YYYYMMDD format)

Hi , i have doubt in bash shell script.. for example my file name is sampledate.sh given command = ./sampledate.sh -d 20100303 -f karthi how to find the next day from 20100303 (YYYYMMDD format) After getting the next day ,changed date and -f argument value will be sent to one java class. ... (13 Replies)
Discussion started by: karthinvk
13 Replies

6. Shell Programming and Scripting

Change the date format from mmddyyyy to yyyymmdd

How do I change the date format from mmddyyyy to yyyymmdd in PERL. Can any one help me please. (3 Replies)
Discussion started by: thankful123
3 Replies

7. Solaris

Date after 5 dates in YYYYMMDD format

Hi Experts, How to get date 5 days after current date in YYYYMMDD format? How do we compare date in YYYYMMDD format? Thanks (1 Reply)
Discussion started by: needyourhelp10
1 Replies

8. Shell Programming and Scripting

Date format to be changed from DDMMYYYY to YYYYMMDD

My requirement is:- there will be files at a location each day with the date format DDMMYYYY. Novawise_Activity_Call_Notes_04022013.txt Novawise_Activity_Inbound_04022013.txt Novawise_Activity_Inbound_05022013.txt Novawise_Activity_Call_Notes_05022013.txt... (8 Replies)
Discussion started by: djrulz123
8 Replies

9. UNIX for Dummies Questions & Answers

Print/cut/grep/sed/ date yyyymmdd on the filename only.

I have this filename "RBD_EXTRACT_a3468_d20131118.tar.gz" and I would like print out the "yyyymmdd" only. I use this command below, but if different command like cut or print....etc. Thanks ls RBD_EXTRACT* | sed 's/.*\(........\).tar.gz$/\1/' > test.txt (9 Replies)
Discussion started by: dotran
9 Replies

10. Shell Programming and Scripting

How to conver YYYYMMDD to MJD format?

I would like to convert YYYYMMDD to MJD format for eg 20041223 converted to 53362 in MJD format i got logic from javascript to covert it to MJD which is long enough function YMDtoMJD (year, month, day) { var year; var monthi var day; var yr = Math.floor (year); ... (1 Reply)
Discussion started by: mandalmanas24
1 Replies
ZIP_ADD(3)						     Library Functions Manual							ZIP_ADD(3)

NAME
zip_add , - .Nm zip_replace add file to zip archive or replace file in zip archive LIBRARY
libzip (-lzip) SYNOPSIS
#include <zip.h> zip_int64_t zip_add(struct zip *archive, const char *name); "struct zip_source *source" int zip_replace(struct zip *archive, zip_uint64_t index); "struct zip_source *source" DESCRIPTION
The function zip_add adds a file to a zip archive, while zip_replace replaces an existing file in a zip archive. The argument archive specifies the zip archive to which the file should be added. name is the file's name in the zip archive (for zip_add ), while index speci- fies which file should be replaced (for zip_replace ). The data is obtained from the source argument. See the zip_source_* functions cited in SEE ALSO. RETURN VALUES
Upon successful completion, zip_add returns the index of the new file in the archive, and zip_replace returns 0. Otherwise, -1 is returned and the error code in archive is set to indicate the error. EXAMPLES
struct zip_source *s; if ((s=zip_source_buffer(archive, buffer, len)) == NULL || zip_add(archive, name, s) 0) { zip_source_free(s); printf("error adding file: %s0, zip_strerror(archive)); } ERRORS
zip_add and zip_replace fail if: [ZIP_ER_EXISTS] There is already a file called name in the archive. (Only applies to zip_add ). [ZIP_ER_INVAL] source or name are NULL, or index is invalid. [ZIP_ER_MEMORY] Required memory could not be allocated. SEE ALSO
libzip(3), zip_source_file(3), zip_source_filep(3), zip_source_function(3), zip_source_zip(3) AUTHORS
Dieter Baron <dillo@giga.or.at> and Thomas Klausner <tk@giga.or.at> NiH March 10, 2009 ZIP_ADD(3)
All times are GMT -4. The time now is 07:54 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy