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Top Forums Shell Programming and Scripting cannot properly employ "or" operator in an if statement (bash) Post 302444800 by goodbenito on Thursday 12th of August 2010 10:25:01 PM
Old 08-12-2010
If I try sheelscripter's suggestion:

Code:
$sername=field_mapping

if [ $sername == *map* ] || [ $sername == *DTI*FA* ]; then echo "Found an FA tag in sername"; else  echo "The variable sername is FA-free"; fi

it is not specific enough, i.e., even though there's the tag "map" in the variable $sername, and I am now calling that in the 'if' statement, it still says that that variable does not contain the tag. In other words, the echo command delivers: "The variable sername is FA-free". So it didn't work.

Any other suggestions? This is bash, by the way. Thanks!
 

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PUZZLE-DIFF(1)															    PUZZLE-DIFF(1)

NAME
puzzle-diff - Compare pictures with libpuzzle SYNOPSIS
[-b <contrast barrier for cropping>] [-c] [-C <max cropping ratio>] [-e] [-E <similarity threshold>] [-h] [-H <max height>] [-l <lambdas>] [-n <noise cutoff>] [-p <p ratio>] [-t] [-W <max width>] <file 1> <file 2> DESCRIPTION
puzzle-diff compares two pictures and outputs the normalized distance. Try puzzle-diff -h for more info. EXAMPLES
Output distance between two images: $ puzzle-diff pic-a-0.jpg pics-a-1.jpg 0.102286 Compare two images, exit with 10 if they look the same, exit with 20 if they don't (may be useful for scripts): $ puzzle-diff -e pic-a-0.jpg pics-a-1.jpg $ echo $? 10 Compute distance, without cropping and with computing the average intensity of the whole blocks: $ puzzle-diff -p 1.0 -c pic-a-0.jpg pic-a-1.jpg 0.0523151 AUTHORS
Frank DENIS libpuzzle at pureftpd dot org SEE ALSO
libpuzzle(3), puzzle_set(3) 2012-05-09 PUZZLE-DIFF(1)
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