How do I check if the argument passed to a script is an integer?
I am writting a script that will take to integers and want to be able to check before I go on.
I am using bourne shell.
Thanks in advance (13 Replies)
I need to accept a number of arguments at command line and print it in reverse order
i use eval `echo x=$1` to capture the argument
#! /bin/sh
counter=0
while
do
eval `echo x=$1`
arg$counter=$x
counter=`expr $counter + 1`
shift
done
but the error keeps... (1 Reply)
i want to write a shell script function that will ftp the files passed in the command line . i have written a shell script for ftp but how will it do for all files passed in command line argument ,
i am passing 4 files as argument
./ftp.sh file1 file2 file3 file4
code written by me... (5 Replies)
I am working on AIX 6.1 issuing #!/bin/sh at the beginning of the script.
I don't understand why $1 is not working as expected. I expect it to hold the value for the first argument coming from the command line consistently - and it is not.
At the beginning of the script starting I do this:... (4 Replies)
I want to make a script that check for the argument passed to it and generates an error in case any character/string argument passed to it.
I am using below code, but its not working. can anyone help.
#!/bin/bash
if ]; then
echo 'An integer argument is passed to the script hence... (3 Replies)
I have a script.
#!/bin/sh
cur_$1_modify_time=Hello
echo "cur_$1_modify_time"
When I run like
sh /root/script1 jj
I expect value "Hello" being assigned to variable "cur_jj_modify_time" and output being "Hello" ie echoing $cur_jj_modify_time
But the output comes as
# sh... (3 Replies)
Hi,
Extremely new to Perl scripting, but need a quick fix without using TEXT::CSV
I need to read in a file, pass any delimiter as an argument, and convert it to bar delimited on the output. In addition, enclose fields within double quotes in case of any embedded delimiters.
Any help would... (2 Replies)
Hi Experts,
I have been trying to work on a simple shell script that will just add the two argument passed to it. Here is what i tried :
#!/bin/bash
welcome(){
echo "Welcome to this Progg. which will accept two parameter"
}
main_logic(){
arg=$#
echo "Number of argument passed is... (4 Replies)
Discussion started by: mukulverma2408
4 Replies
LEARN ABOUT DEBIAN
xpacmdnew
xpacmdnew(3) SAORD Documentation xpacmdnew(3)NAME
XPACmdNew - create a new XPA public access point for commands
SYNOPSIS
#include <xpa.h>
XPA XPACmdNew(char *class, char *name);
DESCRIPTION
Create a new XPA public access point for commands that will share a common identifier class:name. Enter this access point into the XPA name
server, so that it can be accessed by external processes. XPACmdNew() returns an XPA struct.
It often is more convenient to have one public access point that can manage a number of commands, rather than having individual access
points for each command. For example, it is easier to command the ds9 image display using:
echo "colormap I8" | xpaset ds9
echo "scale log" | xpaset ds9
echo "file foo.fits" | xpaset ds9
then to use:
echo "I8" | xpaset ds9_colormap
echo "log" | xpaset ds9_scale
echo "foo.fits" | xpaset ds9_file
In the first case, the commands remain the same regardless of the target XPA name. In the second case, the command names must change for
each instance of ds9. That is, if a second instance of ds9 called DS9 were running, it would be commanded either as:
echo "colormap I8" | xpaset DS9
echo "scale log" | xpaset DS9
echo "file foo.fits" | xpaset DS9
or as:
echo "I8" | xpaset DS9_colormap
echo "log" | xpaset DS9_scale
echo "foo.fits" | xpaset DS9_file
Thus, in cases where a program is going to manage many commands, it generally is easier to define them as commands associated with the
XPACmdNew() routine, rather than as separate access points using XPANew().
When XPACmdNew() is called, only the class:name identifier is specified. Each sub-command is subsequently defined using the XPACmdAdd()
routine.
SEE ALSO
See xpa(7) for a list of XPA help pages
version 2.1.14 June 7, 2012 xpacmdnew(3)