How do I check if the argument passed to a script is an integer?
I am writting a script that will take to integers and want to be able to check before I go on.
I am using bourne shell.
Thanks in advance (13 Replies)
I need to accept a number of arguments at command line and print it in reverse order
i use eval `echo x=$1` to capture the argument
#! /bin/sh
counter=0
while
do
eval `echo x=$1`
arg$counter=$x
counter=`expr $counter + 1`
shift
done
but the error keeps... (1 Reply)
i want to write a shell script function that will ftp the files passed in the command line . i have written a shell script for ftp but how will it do for all files passed in command line argument ,
i am passing 4 files as argument
./ftp.sh file1 file2 file3 file4
code written by me... (5 Replies)
I am working on AIX 6.1 issuing #!/bin/sh at the beginning of the script.
I don't understand why $1 is not working as expected. I expect it to hold the value for the first argument coming from the command line consistently - and it is not.
At the beginning of the script starting I do this:... (4 Replies)
I want to make a script that check for the argument passed to it and generates an error in case any character/string argument passed to it.
I am using below code, but its not working. can anyone help.
#!/bin/bash
if ]; then
echo 'An integer argument is passed to the script hence... (3 Replies)
I have a script.
#!/bin/sh
cur_$1_modify_time=Hello
echo "cur_$1_modify_time"
When I run like
sh /root/script1 jj
I expect value "Hello" being assigned to variable "cur_jj_modify_time" and output being "Hello" ie echoing $cur_jj_modify_time
But the output comes as
# sh... (3 Replies)
Hi,
Extremely new to Perl scripting, but need a quick fix without using TEXT::CSV
I need to read in a file, pass any delimiter as an argument, and convert it to bar delimited on the output. In addition, enclose fields within double quotes in case of any embedded delimiters.
Any help would... (2 Replies)
Hi Experts,
I have been trying to work on a simple shell script that will just add the two argument passed to it. Here is what i tried :
#!/bin/bash
welcome(){
echo "Welcome to this Progg. which will accept two parameter"
}
main_logic(){
arg=$#
echo "Number of argument passed is... (4 Replies)
Discussion started by: mukulverma2408
4 Replies
LEARN ABOUT PHP
eval
EVAL(3) 1 EVAL(3)eval - Evaluate a string as PHP codeSYNOPSIS
mixed eval (string $code)
DESCRIPTION
Evaluates the given $code as PHP.
Caution
The eval(3) language construct is very dangerous because it allows execution of arbitrary PHP code. Its use thus is discouraged.
If you have carefully verified that there is no other option than to use this construct, pay special attention not to pass any user
provided data into it without properly validating it beforehand.
PARAMETERS
o $code
- Valid PHP code to be evaluated. The code mustn't be wrapped in opening and closing PHP tags, i.e. 'echo "Hi!";' must be passed
instead of '<? echo "Hi!"; >'. It is still possible to leave and reenter PHP mode though using the appropriate PHP tags, e.g.
'echo "In PHP mode!"; ?>In HTML mode!<? echo "Back in PHP mode!";'. Apart from that the passed code must be valid PHP. This
includes that all statements must be properly terminated using a semicolon. 'echo "Hi!"' for example will cause a parse error,
whereas 'echo "Hi!";' will work. A return statement will immediately terminate the evaluation of the code. The code will be exe-
cuted in the scope of the code calling eval(3). Thus any variables defined or changed in the eval(3) call will remain visible
after it terminates.
RETURN VALUES eval(3) returns NULL unless return is called in the evaluated code, in which case the value passed to return is returned. If there is a
parse error in the evaluated code, eval(3) returns FALSE and execution of the following code continues normally. It is not possible to
catch a parse error in eval(3) using set_error_handler(3).
EXAMPLES
Example #1
eval(3) example - simple text merge
<?php
$string = 'cup';
$name = 'coffee';
$str = 'This is a $string with my $name in it.';
echo $str. "
";
eval("$str = "$str";");
echo $str. "
";
?>
The above example will output:
This is a $string with my $name in it.
This is a cup with my coffee in it.
NOTES
Note
Because this is a language construct and not a function, it cannot be called using variable functions.
Tip
As with anything that outputs its result directly to the browser, the output-control functions can be used to capture the output of
this function, and save it in a string (for example).
Note
In case of a fatal error in the evaluated code, the whole script exits.
SEE ALSO call_user_func(3).
PHP Documentation Group EVAL(3)