Sponsored Content
Top Forums UNIX for Dummies Questions & Answers Help with seq (print a series of dates) Post 302443738 by uiop44 on Tuesday 10th of August 2010 02:47:30 AM
Old 08-10-2010
Help with seq (print a series of dates)

Assuming one does not have such luxuries as bash, zsh, jot, rs, perl, etc. what is the most elegant way to print out a formatted date series like this:

Code:
01-01-2010
01-02-2010
01-03-2010
...
02-01-2010
02-02-2010
...

Can I accomplish this with just basic shell builtins and seq, or perhaps other "ubiquitous" UNIX software tools? Maybe this is a job for awk and an incremented array?
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Compare dates in a field and print the latest date row

Hi, I need a shell script which should find the latest date in the field of file and print that line only. For eg., I have a file /date.log Name Date Status IBM 06/06/07 close DELL 07/27/07 open DELL 06/07/07 open : : : From... (1 Reply)
Discussion started by: cvkishore
1 Replies

2. Shell Programming and Scripting

print 10 characters in series

suppose fileA kanika123ABC 1222222222222222 raciat5678ty 1221123333331121 jessica78ulllo 2233243223333333 so output shud be print only first 10 characters in series and rest remain same kanika123A 1222222222222222 raciat5678 1221123333331121 jessica78u ... (1 Reply)
Discussion started by: cdfd123
1 Replies

3. Shell Programming and Scripting

declaring variable with for $(seq)

Hi guys. i have the following script: 1 #!/bin/bash 2 linkcount=$(grep "/portal" tickets | wc -l) 3 grep "/portal" tickets > links 4 for i in $(seq 1 $linkcount); do 5 echo "BLYAT" 6 let link$i=$(sed -n "$i"p links) 7 echo $ 8 done the problem is, that "let" can`t... (1 Reply)
Discussion started by: neverhood
1 Replies

4. Shell Programming and Scripting

Need script to generate all the dates in DDMMYY format between 2 dates

Hello friends, I am looking for a script or method that can display all the dates between any 2 given dates. Input: Date 1 290109 Date 2 010209 Output: 300109 310109 Please help me. Thanks. :):confused: (2 Replies)
Discussion started by: frozensmilz
2 Replies

5. UNIX for Dummies Questions & Answers

print all dates 100 days from current date

can anyone please suggest me on ideas to write a script which has to go back to 100 days from 'current date' and print the date of each day starting from 100th day to current day. (korn shell please) Thanks Pavan (5 Replies)
Discussion started by: pavan_test
5 Replies

6. Shell Programming and Scripting

Using Seq As A Variable With Padded Digits

Hi all. Im trying to use a sequence in a while loop like this below. I need it for navigating a year, month, day folder structure where a user can input the start date and have it go to the desired end date. The script will grab a certain file on each day then move onto the next. Ive got all that... (3 Replies)
Discussion started by: Grizzly
3 Replies

7. Shell Programming and Scripting

Using seq (Or alternative)

I usually just browse the forum/google for answers, however I've been stuck on a problem for a number of hours now and I've decided to join up and actually ask I've searched the forum ad naseum in an attempt to find answer to my query, however so far I have been unsuccessful. I'm no expert... (3 Replies)
Discussion started by: gtc
3 Replies

8. Shell Programming and Scripting

How to show first 0 using seq or +1 count?

Greetings, Using linux based OS and KSH. I m trying to make a simple script to parse some logs to show a count per hour on a specific alarm starting from midnight to the current hour. So I format my "HOUR" variable to show the current time and so I can use it in the following bit of code.... (6 Replies)
Discussion started by: Sekullos
6 Replies

9. UNIX for Dummies Questions & Answers

RNA-seq analysis

I am processing RNA-seq data files that have been aligned using RUM. One of the output files is a *.sam that includes: Unique alignments Non-unique alignments original read files I want to extract only the unique alignments by pulling out alignments that have "IH:i:1" (indicates this read... (2 Replies)
Discussion started by: genGirl23
2 Replies

10. Shell Programming and Scripting

Easy seq Question

Hi! I'm trying to do this: 1 - 2 - 3 - 4 - 5 - I'm using seq for this: seq 1 20 > filename.txt How do I get the "-"? I've tried -f per man but can't get anything to work. Also, is there an easier or better way than using sequence? Thanks! (6 Replies)
Discussion started by: TonyBe
6 Replies
Path::Dispatcher::Cookbook(3pm) 			User Contributed Perl Documentation			   Path::Dispatcher::Cookbook(3pm)

NAME
Path::Dispatcher::Cookbook - A cookbook for Path::Dispatcher RECIPES
How can I change the path delimiter from a space ' ' to a slash '/'? When importing the Path::Dispatcher::Declarative sugar, specify the "token_delimiter" option for the "default" group. package My::Dispatcher; use Path::Dispatcher::Declarative -base, -default => { token_delimiter => '/', }; Or define a subclass of Path::Dispatcher::Declarative with a "token_delimiter" method: package Web::Dispatcher::Maker; use base 'Path::Dispatcher::Declarative'; use constant token_delimiter => '/'; package My::Dispatcher; use Web::Dispatcher::Maker -base; How can I do rule chaining (like in Catalyst)? You can use a "chain" rule approximate chaining behavior: package MyDispatcher; use Path::Dispatcher::Declarative -base; under show => sub { chain { print "Displaying "; }; on inventory => sub { print "inventory: "; ... }; on score => sub { print "score: "; ... }; }; package main; MyDispatcher->run("show inventory"); # "Displaying inventory: ..." MyDispatcher->run("show score"); # "Displaying score: ..." How can I configure tab completion for shells? First add a dispatcher rule for generating completions based on the path. Here we name it _gencomp, so that if the user types "app _gencomp hel" it will print out the various completions of "hel". on qr/^_gencomps*(.*)/ => sub { my $prefix = shift->pos(1); $prefix = "" if !defined($prefix); print "$_ " for dispatcher->complete($prefix); }; Then tell your shell about how to use _gencomp. For zsh it might look like this (replace "APP" with your binary name): /usr/share/zsh/site-functions/_APP: #compdef APP typeset -a APP_completions APP_completions=($($words[1] _gencomp $words[2,-1])) compadd $APP_completions For bash it might look like this: /etc/bash_completion.d/APP.bash: function _APP_() { COMPREPLY=($($1 _gencomp ${COMP_WORDS[COMP_CWORD]})) } complete -F _APP_ APP perl v5.12.4 2011-08-30 Path::Dispatcher::Cookbook(3pm)
All times are GMT -4. The time now is 05:22 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy