Hi,
I'm trying to accomplish the following and would like some suggestions or possible bash script examples that may work
I have a directory that has a list of log files that's periodically dumped from a script that is crontab that are rotated 4 generations. There will be a time stamp that is... (4 Replies)
how to copy lines from a log file based on timestamp.
INFO (RbrProcessFlifoEventSessionEJB.java:processFlight:274) - E_20080521_110754_967: rbrAciInfoObjects listing complete!
INFO (RbrPnrProcessEventSessionEJB.java:processFlight:197) - Event Seq: 1647575217; Carrier: UA; Flt#: 0106; Origin:... (1 Reply)
Hi Xpert Out There
I have a lots of file in this path :
-rw-r----- 1 oracle dba 3954176 Dec 21 2006 1_2008.dbf
-rw-r----- 1 oracle dba 887808 Dec 21 2006 1_2009.dbf
-rw-r----- 1 oracle dba 143872 Dec 21 2006 1_2010.dbf
-rw-r----- 1 oracle dba ... (3 Replies)
Hi all.
I have a database log file in which log data get appended to it daily. I want to do a automatic maintainence of this log by going through the log and deleting lines belonging to a certain date.
How should i do it? Please help. Thanks.
Example. To delete all lines prior to Jun... (4 Replies)
Hello. I'm not nearly good enough with awk/perl to create the logfile scraping script that my boss is insisting we need immediately. Here is a brief 3-line excerpt from the access.log file in question (actual URL domain changed to 'aaa.com'):
209.253.130.36 - - "GET... (2 Replies)
I'm still up trying to figure this out and it is driving me nuts.
I have a log file which has a basic format of this...
2010-10-10 22:25:42
Init block 'UA Deployment Date': Dynamic refresh of repository scope variables has failed.
The ODBC function has returned an error. The database... (4 Replies)
Hi,
I have a csv file with old data..i need to have only last 30 days from the current dateof data in the file.The fourth field in the file is a date field.i need to write a script to delete the old data by comparing the the fourth field with the (current date -30).I need to delete the rows in... (2 Replies)
To delete log files content older than 30 days and append the lastest date log file date in the respective logs
I want to write a shell script that deletes all log files content older than 30 days and append the lastest log file date in the respective logs
This is my script
cd... (2 Replies)
Hello All !
I need your help on this case,
I have a csv file with this:
ITEM105;ARI FSR;2016-02-01 08:02;243
ITEM101;ARI FSR;2016-02-01 06:02;240
ITEM032;RNO TLE;2016-02-01 11:03;320
ITEM032;RNO TLE;2016-02-02 05:43;320
ITEM032;RNO TLE;2016-02-01 02:03;320
ITEM032;RNO... (2 Replies)
Dear Experts,
I have a log file that contains a timestamp, I would like to filter record from that file based on timestamp. For example refer below file -
cat sample.txt
Jan 19 20:51:48 mukul-Vostro-14-3468 systemd: pam_unix(systemd-user:session): session opened for user root by (uid=0)... (6 Replies)
Discussion started by: mukulverma2408
6 Replies
LEARN ABOUT DEBIAN
xcalpr
XCALPR(1) General Commands Manual XCALPR(1)NAME
xcalpr - print xcal calendar entries
SYNTAX
xcalpr [ -c ][ -x ][ -f file ][ -d dir ][ -u user ][ date-spec ]
DESCRIPTION
Xcalpr prints the contents of the xcal files. It is intended to be used in situations when you have no access to an X screen. It can also
be used to generate entries for the standard UNIX calendar program.
With no arguments, it prints any entries that exist for the next seven days. The program also reads the contents of the seven daily files
and prints them at the appropriate point in the output stream. Each line in the output is preceded by the day of the week, the day of the
month, the month and the year.
Xcalpr can be given a date specification to select months and years. If the date spec consists of just a year number, then all the data
for that year is printed. For example:
xcalpr 1994
will print all the data for 1994. Several years can be specified.
If you give the name of a month, then the data for that month in the current year will be printed. If the month is in the past, then the
data for that month next year will be printed. For example, if
xcalpr oct jan
is typed in August, xcalpr will print October in the current year and January next year.
You can select a particular year by adding the number after any months that you need printing:
xcalpr oct nov 1994
will print October and November in 1994.
There are a couple of special `month' names. The name rest will print the data for the rest of the month, starting tomorrow. The rest
argument is not recognised if you give a year as a parameter. If tomorrow happens to be the first day of the next month, then all the data
for next month will be printed. The name next prints all the data for next month.
OPTIONS
The -c option causes xcalpr to output lines suitable for input to the standard UNIX calendar program.
The -d switch is followed by a directory name and specifies an alterative location for your Calendar directory. Your home directory is
prepended if the name doesn't start with a slash or a dot.
The -f option is followed by a file name and xcalpr will write it's output to that file, rather than standard output.
The -u option is followed by a user name and dumps their calendar files rather than yours.
The -x option makes xcalev operate with Calendar files that are compatible with the xcalendar program.
FILES
$HOME/Calendar/*
xc<dd><Mon><Year> A data file is day, Month in three letter format and the year.
xy<Year> A year directory.
xw<Day> A data file for the weekly code, one per day.
SEE ALSO xcal(1), xcalev(1), xcal_cal(1)AUTHOR
Copyright 1993 by Peter Collinson, Hillside Systems All rights reserved.
This product includes software developed by the University of California, Berkeley and its contributors.
X Version 11 R5 October 1993 XCALPR(1)