Sponsored Content
Top Forums UNIX for Dummies Questions & Answers solved - removing last n char in every line Post 302442082 by fpmurphy on Tuesday 3rd of August 2010 08:47:37 AM
Old 08-03-2010
You can pass a variable to sed as shown here:
Code:
# cat infile
testt
test1
test11
testz
testX

Code:
$ CNT=3
$ echo $CNT
3
$ sed "s/.\{${CNT}\}$//" infile
te
te
tes
te
te
$

 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

how first char in odd line and second char in even line

Hi I m having ifconfig -a o/p like sbanlab1:ksh# ifconfig -a | egrep "flags|inet" | awk -F' ' '{print $1,$2}' lo0: flags=2001000849<UP,LOOPBACK,RUNNING,MULTICAST,IPv4,VIRTUAL> inet 127.0.0.1 lo0:1: flags=2001000849<UP,LOOPBACK,RUNNING,MULTICAST,IPv4,VIRTUAL> inet 127.0.0.1 bge0:... (1 Reply)
Discussion started by: tarunn.dubeyy
1 Replies

2. Shell Programming and Scripting

Removing special char's with sed

Hi, I've a txt file which contains the following kind of listed data 18971 ./aosrp18.r 15340 ./aosrp12.r 22996 ./aosrp08.r 17125 ./aosrp06.r I'm trying to get rid of the ./ in the file and have tried the following with sed but I'm not getting the correct result... I'm not sure what way... (7 Replies)
Discussion started by: Jazmania
7 Replies

3. Shell Programming and Scripting

[Solved] Problem in reading a file line by line till it reaches a white line

So, I want to read line-by-line a text file with unknown number of files.... So: a=1 b=1 while ; do b=`sed -n '$ap' test` a=`expr $a + 1` $here do something with b etc done the problem is that sed does not seem to recognise the $a, even when trying sed -n ' $a p' So, I cannot read... (3 Replies)
Discussion started by: hakermania
3 Replies

4. UNIX for Dummies Questions & Answers

[Solved] Help with using tr - Removing white spaces

Hi, I have a file that contains whitespaces with spaces and spaces and tabs on each line and am wanting to remove the whitespaces. My version of sed is one that does not recognize \t etc. The sed and awk one-liners below that I found via Google both does not work. So my next best... (3 Replies)
Discussion started by: newbie_01
3 Replies

5. UNIX for Dummies Questions & Answers

[solved]removing characters from a mass of file names

I found a closed thread that helped quite a bit. I tried adding the URL, but I can't because I don't have enough points... ? Modifying the syntax to remove ! ~ find . -type f -name '*~\!]*' | while IFS= read -r; do mv -- "$REPLY" "${REPLY//~\!]}"; done These messages are... (2 Replies)
Discussion started by: rabidphilbrick
2 Replies

6. Shell Programming and Scripting

Formatting File having big single line into 95 Char Per Line

Hi All, I have 4 big files which contains one big line containing formatted character records, I need to format each file in such way that each File will have 95 Characters per line. Last line of each file will have newline character at end. Before:- File Name:- File1.dat 102 121340560... (10 Replies)
Discussion started by: lancesunny
10 Replies

7. Programming

C++ Removing = from char*

I have a char* str. Suppose str="medium"; I want to check if str has "=" as first non blank position, if it exists, I want to remove it Currently I am checking using if (optarg == '=') cout << "Found =" << endl; (2 Replies)
Discussion started by: kristinu
2 Replies

8. UNIX for Dummies Questions & Answers

[Solved] Removing an 8 character string

Edit: Figured it out. Close the thread please. Solution: \{8}\] edit by bakunin: no need to close the thread, but i changed the title to SOLVED. Thanks for writing a follow-up. (0 Replies)
Discussion started by: unknownn
0 Replies

9. Shell Programming and Scripting

How to separate one line to mutiple line based on one char?

Hi Gurus, I need separate one file which is one huge line to mutiple line. file like abcd # bcd # def # fge # ged I want to get abcd bcd def fge ged Thanks in advance (4 Replies)
Discussion started by: ken6503
4 Replies

10. Shell Programming and Scripting

[Solved] Modifying/Removing Timestamps from a filename

So given filenames of varying lengths, I was wondering how I would remove or modify appended timestamps of the current date DD-MM-YY. So say: test_DD-MM-YY.txt coolbeans_DD-MM-YY.pdf And what I expect the output to be: test.txt coolbeans.pdf Thanks :) (2 Replies)
Discussion started by: sodaboyz
2 Replies
gpgwrap(1)						      General Commands Manual							gpgwrap(1)

NAME
gpgwrap - a small wrapper for gpg SYNOPSIS
gpgwrap -V gpgwrap -P [-v] [-i] [-a] [-p <file>] gpgwrap -F [-v] [-i] [-a] [-c] [-p <file>] [-o <name>] [--] <file> [<file> ... ] gpgwrap [-v] [-i] [-a] [-p <file>] [-o <name>] [--] gpg [gpg options] DESCRIPTION
The GNU Privacy Guard (gpg) supplies the option --passphrase-fd. This instructs gpg to read the passphrase from the given file descriptor. Usually this file descriptor is opened before gpg is executed via execvp(3). Exactly that is what gpgwrap is doing. The passphrase may be passed to gpgwrap in 4 ways: * as file path, whereat the passphrase is stored as plain text in the file * it is piped from another program to the stdin of gpgwrap * through the GPGWRAP_PASSPHRASE environment variable * gpgwrap prompts for it With no precautions the first point undermines the secure infrastructure gpg provides. But in pure batch oriented environments this may be what you want. Otherwise if you are willing to enter passphrases once and don't want them to be stored as plain text in a file gpg-agent is what you are looking for. Another security objection could be the use of the environment variable GPGWRAP_PASSPHRASE which contains the passphrase and may be read by other processes of the same user. OPTIONS
-V, --version Print out version and exit. -P, --print Get the passphrase and print it mangled to stdout. -F, --file Read gpg commands from the given files. If <file> is - it is read from stdin. Exactly one command per line is expected. The given line is handled in the following way: * In the first place the passphrase is mangled. This means that unusual characters are replaced by their backslash escaped octal numbers. * Secondly the mangled passphrase is stored in the environment variable GPGWRAP_PASSPHRASE. * "exec gpgwrap -- " is prepended to each line, before the result is passed as argument to "sh -c". -h, --help Print out usage information. -v, --verbose Increase verbosity level. -i, --interactive Always prompt for passphrase (ignores -p and the environment variable). -a, --ask-twice Ask twice if prompting for a passphrase. -c, --check-exit-code While reading gpg commands from a file, gpgwrap ignores per default the exit code of its child processes. This option enables the check of the exit code. If a child terminates abnormal or with an exit code not equal 0 gpgwrap stops immediately and does return with this exit code. See also section BUGS. -p <file>, --passphrase-file <file> Read passphrase from <file>. If <file> is - it is read from stdin. The passphrase is expected to be in plain text. If this option is not given the passphrase will be taken either from the environment variable GPGWRAP_PASSPHRASE or it will be prompted on the controlling tty if the environment variable is not set. -o <name>, --option-name <name> Specify the name of the "--passphrase-fd" option understood by the program to be executed. This is useful if you want to use gpg- wrap in combination with other programs than gpg. LIMITATIONS
The given passphrase is subject to several limitations depending on the way it was passed to gpgwrap: * There is a size limitation: the passphrase should be not larger than some kilobytes (examine the source code for the exact limit). * gpgwrap allows you to use all characters in a passphrase even 00, but this does not mean that gpg will accept it. gpg may reject your passphrase or may only read a part of it, if it contains characters like 12 (in C also known as ). * If you set the environment variable GPGWRAP_PASSPHRASE you should take special care with the backslash character, because gpgwrap uses backslash to escape octal numbers, (see option -F). Therefore write backslash itself as octal number: 134. EXAMPLES
1. gpgwrap -p /path/to/a/secret/file gpg -c -z 0 --batch --no-tty --cipher-algo blowfish < infile > outfile Read passphrase from /path/to/a/secret/file and execute gpg to do symmetric encryption of infile and write it to outfile. 2. gpgwrap -i -a gpg -c -z 0 --batch --no-tty --cipher-algo blowfish < infile > outfile Same as above except that gpgwrap prompts twice for the passphrase. 3. gpgwrap -F -i - <<EOL gpg --decrypt --batch --no-tty < "$HOME/infile1" > "$HOME/outfile1" gpg --decrypt --batch --no-tty < "$HOME/infile2" > "$HOME/outfile2" gpg --decrypt --batch --no-tty < "$HOME/infile3" > "$HOME/outfile3" gpg --decrypt --batch --no-tty < "$HOME/infile4" > "$HOME/outfile4" EOL gpgwrap prompts for the passphrase and executes four instances of gpg to decrypt the given files. 4. GPGWRAP_PASSPHRASE="mysecretpassphrase" export GPGWRAP_PASSPHRASE gpgwrap -F -c -v /tmp/cmdfile1 - /tmp/cmdfile2 <<EOL gpg --decrypt --batch --no-tty < "$HOME/infile1" > "$HOME/outfile1" gpg --decrypt --batch --no-tty < "$HOME/infile2" > "$HOME/outfile2" gpg --decrypt --batch --no-tty < "$HOME/infile3" > "$HOME/outfile3" gpg --decrypt --batch --no-tty < "$HOME/infile4" > "$HOME/outfile4" EOL Same as above except that gpgwrap gets the passphrase via the environment variable, reads commands additionally from other files and checks the exit code of every gpg instance. This means if one gpg command has a non zero exit code, no further commands are executed. Furthermore gpgwrap produces verbose output. 5. GPGWRAP_PASSPHRASE="$(gpgwrap -P -i -a)" export GPGWRAP_PASSPHRASE find . -maxdepth 1 -type f | while read FILE; do FILE2="$FILE.bz2.gpg" bzip2 -c "$FILE" | gpgwrap gpg -c -z 0 --batch --no-tty --cipher-algo blowfish > "$FILE2" && touch -r "$FILE" "$FILE2" && rm -f "$FILE" done Read in passphrase, compress all files in the current directory, encrypt them and keep date from original file. 6. find . -maxdepth 1 -type f -name '*.bz2.gpg' | awk '{ printf("gpg --decrypt --batch --no-tty --quiet "); printf("--no-secmem-warning < %s ", $0); }' | gpgwrap -F -i -c - | bzip2 -d -c - | grep -i 'data' Decrypt all *.bz2.gpg files in the current directory, decompress them and print out all occurances of data. If you pipe the result to less you get into trouble because gpgwrap and less try to read from the TTY at the same time. In such a case it is better to use the environment variable to give the passphrase (the example above shows how to do this). 7. GPGWRAP_PASSPHRASE="$(gpgwrap -P -i -a)" export GPGWRAP_PASSPHRASE gpgwrap -P | ssh -C -x -P -l user host " GPGWRAP_PASSPHRASE="$(cat)" ... " Prompt for a passphrase twice and write it to the GPGWRAP_PASSPHRASE environment variable. 8. echo -n "Passphrase: " stty -echo read GPGWRAP_PASSPHRASE echo stty echo export GPGWRAP_PASSPHRASE Another way to prompt manually for the passphrase. It was needed in combination with older versions of gpgwrap, because they did not upport -P. Be aware that with this method no automatic conversion to backslash escaped octal numbers takes place. 9. echo "mysecretpassphrase" | gpg --batch --no-tty --passphrase-fd 0 --output outfile --decrypt infile Cheap method to give passphrase to gpg without gpgwrap. Note that you can't use stdin to pass a file to gpg, because stdin is already used for the passphrase. 10. gpg --batch --no-tty --passphrase-fd 3 3< /path/to/a/secret/file < infile > outfile This is a more advanced method to give the passphrase, it is equivalent to Option -p of gpgwrap. This example should at least work with the bash. 11. gpg --batch --no-tty --passphrase-fd 3 3< <(echo "mysecretpassphrase") < infile > outfile Like above, but the passphrase is given directly. This example should at least work with the bash. BUGS
In version 0.02 of gpgwrap the exit code of gpg was only returned if gpgwrap read the passphrase from a file. Since version 0.03, only -F omits exit code checking by default, but it can be enabled with -c. SEE ALSO
gpg, gpg-agent AUTHOR
Karsten Scheibler gpgwrap 0.04 gpgwrap(1)
All times are GMT -4. The time now is 05:15 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy