Hi,
I have an expression using grep and nawk that captures the ID number of a given Unix process. It gets printed to screen but I don't know how to declare a variable to this returned value!
For example,
ps -ef|grep $project | grep -v grep | nawk '{print $2}'
This returns my number. How... (2 Replies)
Hi,
I am passing a variable to a unix function.
However when I try to assign the value to another variable like
typeset -i I_CACHE_VAL=$2
Is this because of String to Integer conversion?
I get an error.
Please help me with thsi.
Thanks (2 Replies)
Hello,
I am in following situation.-
COUNT=`ls -l | wc -l`
echo $COUNT
---> 26
NO_OF_FILES=$COUNT-1
echo $NO_OF_FILES
---> 26-1
Here, I want the output to be 25. How could I do this. It seems simple, but I am not getting it. Please help me. (2 Replies)
Hi,
I have multiple functions that can be called by any shell script. These functions have inbuilt echo statements to logs their activity into a log file. When I run multiple shell scripts that call these functions, they all log into the same log file and I am not able to differentiate which... (2 Replies)
I read 3 variables from from Inputfile.txt the third one "startnumber" is a number when i compare it with 9 ($startnumber -le 9) it give's me a "unary operator expected", i know that -le is for number comparison. What i need is to convert $startnumber to integer (i have try to do it with expr but... (8 Replies)
hello,
i am writing a script that takes the UID from the PASSWD and then i want
to increse the Number by one. for the Next user.
i cannot get this to work that a variable is as interger
example:
set i = 0
set $i = $+1
it's in tcsh if it's mather (10 Replies)
Hi Guys,
i guess there is a several ways to grub the strings from date and time
like THISMONTH='/bin/date +%m'
but the hard part is to add or sub that string to a variable
i tried to use let command
TWOMONTHSAGO=$THISMONTH
declare -i TWOMONTHSAGO
let TWOMONTHSAGO-=2
but there... (1 Reply)
In log directory file contain log files and files contain some unique job name which is dynamically created (example=55555 ),if job get 55555 then send alert message, but after next run if it find ---55555 then no need send alert message
While checking the first job name you are capturing the Job... (3 Replies)
Discussion started by: Kalia
3 Replies
LEARN ABOUT DEBIAN
incr
incr(3tcl) Tcl Built-In Commands incr(3tcl)__________________________________________________________________________________________________________________________________________________NAME
incr - Increment the value of a variable
SYNOPSIS
incr varName ?increment?
_________________________________________________________________DESCRIPTION
Increments the value stored in the variable whose name is varName. The value of the variable must be an integer. If increment is supplied
then its value (which must be an integer) is added to the value of variable varName; otherwise 1 is added to varName. The new value is
stored as a decimal string in variable varName and also returned as result.
Starting with the Tcl 8.5 release, the variable varName passed to incr may be unset, and in that case, it will be set to the value incre- |
ment or to the default increment value of 1.
EXAMPLES
Add one to the contents of the variable x:
incr x
Add 42 to the contents of the variable x:
incr x 42
Add the contents of the variable y to the contents of the variable x:
incr x $y
Add nothing at all to the variable x (often useful for checking whether an argument to a procedure is actually integral and generating an
error if it is not):
incr x 0
SEE ALSO expr(3tcl)KEYWORDS
add, increment, variable, value
Tclincr(3tcl)