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Full Discussion: Find and replace with variable using sed or awk
Top Forums Shell Programming and Scripting Find and replace with variable using sed or awk Post 302437775 by raghavendra.cse on Friday 16th of July 2010 06:44:22 AM
Old 07-16-2010
i am using ksh it is fialing with invalid option

Code:
sed: illegal option -- i



---------- Post updated at 05:44 AM ---------- Previous update was at 04:42 AM ----------

i achived it using

Code:
while read all; do

   find=$(echo $all| awk -F"," '{print $2}' )
   rep=$(echo $all| awk -F"," '{print $1}' )
   echo "$find and $rep \n" 
   sed -e "s/^$find/$rep/g" email.temp | grep "$rep" | grep -v "_" >> email.file
   
  done < r3

Last edited by radoulov; 07-16-2010 at 07:46 AM.. Reason: Please use code tags!
 

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LEARN ABOUT XFREE86

zgrep

ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME

       zgrep - search possibly compressed files for a regular expression

SYNOPSIS

       zgrep [ grep_options ] [ -e ] pattern filename...

DESCRIPTION

       Zgrep  invokes  grep  on  compressed  or  gzipped  files.   These  grep	options  will  cause  zgrep  to  terminate  with  an  error  code:
       (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*).  All other options specified are passed directly to grep.  If no file is specified,  then  the
       standard input is decompressed if necessary and fed to grep.  Otherwise the given files are uncompressed if necessary and fed to grep.

       If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.

EXIT CODE

       2 - An option that is not supported was specified.

AUTHOR

       Charles Levert (charles@comm.polymtl.ca)

SEE ALSO

       grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)

																	  ZGREP(1)
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