I have a variable whose value is
I="user1:x:1100:1200:ID for user1:/home/user1:/bin/ssh-dummy-shell"
I want to replace the last part '/bin/ssh-dummy-shell' with '/bin/true'
I tried using sed but it garbled
sed 's/\/bin\/ssh-dummy-shell/\/bin\/true' $I
Thanks for the help (5 Replies)
Is there an easy way of doing this
cat file1
jkasjhjgfg LTRIM(RTRIM(aa_bb_cde))
aragsfdg LTRIM(RTRIM(aa_bb_cde)) aregfafdgfg
sdgsfdagdfg gadfg
eafgsadgsa
asdgsfdgag LTRIM(RTRIM(aa_bb_cde)) rfghsdfhd
I want to replace each occurence of LTRIM(RTRIM($x)) with
LENGTH(LTRIM(RTRIM($x)))=0... (4 Replies)
Hi :)
I have some problems with "FOR"...
I have a text file in this format:
name1
www.link1/random_number
name2
www.link2/random_number
name3
www.link3/random_number
...
(Names and info changes)
Now, I need: (4 Replies)
Hi this is my first time posting ever. I'm relatively new in using AWK/SED, I've been trying many a solution. I'm trying to replace the 59th column in a file where if I encounter '' then I would like to replace it with the word NULL.
example
0 , '' , '' , 0 , 195.538462
change it to
0... (5 Replies)
Hi Everyone,
I am new to this forum and new to sed/awk programming too !!
I need to find particular string in file1(text file) and replace it with a value from another text file(file2) the file2 has only one line and the value to be replaced with is in the second column.
file 1:
(assert (=... (21 Replies)
Hi all,
Hereby wish to have your advise for below:
Main concept is
I intend to get current directory of my script file.
This script file will be copied to /etc/init.d.
A string in this copy will be replaced with current directory value.
Below is original script file:
... (6 Replies)
Hi,
I have a ksh script where I am trying to mask the password in the log files.
$loc - is my directory
$PGUIDE_DB_USER_PSW - is a variable that holds the password I am looking for
find $loc/logs -type f -exec sed -i "s/$PGUIDE_DB_USER_PSW/*****/"g {} \;
I get an error:
... (2 Replies)
All,
I have thousands of lines in a file with following format
DATA=_ONE_XXX_YYY_CCC_HHHG_
DATA1=_GGG_JJJJ_HHH_UUU_JJJJ_HHHH_LLL_
DATA3=_MMM_GG_NN_QQQQ_FFF_III_
I want to replace _ with . by ignoring the first (=_) and last (_)
So that out put should looks like... (4 Replies)
Greetings. I have a three column file, and there are some numbers in the second column that are <1. However I need all numbers to be positive, thus need to replace all those numbers with just one. I feel like there must be a simple way to use awk to find these numbers and sed to replace but can't... (5 Replies)
Hi All
I have one file with multiple lines in it, each line has static text and some variable enclosed in <<filename>> as well. e.g. as below
123, <<file1.txt>> this is my name, I stay at <<city.txt>> Thanks for visiting
348384y, this is my name <<fileabc.txt>>, I stay at near the mall of... (8 Replies)
Discussion started by: reldb
8 Replies
LEARN ABOUT MOJAVE
getopt
GETOPT(1) BSD General Commands Manual GETOPT(1)NAME
getopt -- parse command options
SYNOPSIS
args=`getopt optstring $*` ; errcode=$?; set -- $args
DESCRIPTION
The getopt utility is used to break up options in command lines for easy parsing by shell procedures, and to check for legal options.
Optstring is a string of recognized option letters (see getopt(3)); if a letter is followed by a colon, the option is expected to have an
argument which may or may not be separated from it by white space. The special option '--' is used to delimit the end of the options. The
getopt utility will place '--' in the arguments at the end of the options, or recognize it if used explicitly. The shell arguments ($1 $2
...) are reset so that each option is preceded by a '-' and in its own shell argument; each option argument is also in its own shell argu-
ment.
EXAMPLES
The following code fragment shows how one might process the arguments for a command that can take the options -a and -b, and the option -o,
which requires an argument.
args=`getopt abo: $*`
# you should not use `getopt abo: "$@"` since that would parse
# the arguments differently from what the set command below does.
if [ $? != 0 ]
then
echo 'Usage: ...'
exit 2
fi
set -- $args
# You cannot use the set command with a backquoted getopt directly,
# since the exit code from getopt would be shadowed by those of set,
# which is zero by definition.
for i
do
case "$i"
in
-a|-b)
echo flag $i set; sflags="${i#-}$sflags";
shift;;
-o)
echo oarg is "'"$2"'"; oarg="$2"; shift;
shift;;
--)
shift; break;;
esac
done
echo single-char flags: "'"$sflags"'"
echo oarg is "'"$oarg"'"
This code will accept any of the following as equivalent:
cmd -aoarg file file
cmd -a -o arg file file
cmd -oarg -a file file
cmd -a -oarg -- file file
SEE ALSO sh(1), getopt(3)DIAGNOSTICS
The getopt utility prints an error message on the standard error output and exits with status > 0 when it encounters an option letter not
included in optstring.
HISTORY
Written by Henry Spencer, working from a Bell Labs manual page. Behavior believed identical to the Bell version. Example changed in FreeBSD
version 3.2 and 4.0.
BUGS
Whatever getopt(3) has.
Arguments containing white space or embedded shell metacharacters generally will not survive intact; this looks easy to fix but isn't. Peo-
ple trying to fix getopt or the example in this manpage should check the history of this file in FreeBSD.
The error message for an invalid option is identified as coming from getopt rather than from the shell procedure containing the invocation of
getopt; this again is hard to fix.
The precise best way to use the set command to set the arguments without disrupting the value(s) of shell options varies from one shell ver-
sion to another.
Each shellscript has to carry complex code to parse arguments halfway correcty (like the example presented here). A better getopt-like tool
would move much of the complexity into the tool and keep the client shell scripts simpler.
BSD April 3, 1999 BSD