below are the scripts that i've edited based on my understanding:
Code:
#!/bin/sh
dir=/home/devusr02/nadiah/input/file_name.log
msg=`tail -1 $dir`
name=${msg%% Failed *}
status=Failed
if [ ${#name} -eq ${#msg} ]
then
# length of string is same as original message
# ie replace matched nothing - assume success string
# status=success
name=${msg%% successfully *}
status=Success
fi
datetime=${msg##*ran on } # remove "ran on " and all proceeding
datetime=${datetime%% SST *} # remove " SST " and all following
time=${datetime##* } # remove last space and all proceeding
date=${datetime% *} # remove last space and all following
echo "$msg"
echo "$name"
echo "$status"
the script output:
if success:
Code:
report_name successfully ran on Tue Jul 11 23:15:00 SST 2010.
report_name
Success
00:15:00
if failed:
Code:
ERROR: report_name is Failed on Tue Jul 11 23:15:00 SST 2010. ErrorCode : 500
ERROR: report_name is
Failed
00:15:00
BUT the output for name should be only "report_name" instead of "ERROR: report_name is" if failed
Moderator's Comments:
Use code tags, please...
---------- Post updated at 04:57 AM ---------- Previous update was at 03:51 AM ----------
one more question..
i wonder if is it possible if the date can be set as : 11 Jul 2010
based on script below,
Code:
datetime=${msg##*ran on } # remove "ran on " and all proceeding
datetime=${datetime%% SST *} # remove " SST " and all following
time=${datetime##* } # remove last space and all proceeding
date=${datetime% *} # remove last space and all following
the output is : "Tue Jul 11"
is there any other easier way to make the date as 11 Jul 2010 instead of i need to do step by step and combine the all the variable for example : echo "$day" "$month" "$year" ??
in addition, can someone guide me on how to eliminate day in front of the month " Tue Jul 11" as the day is changing from monday-sunday..
thanks.
Last edited by Scott; 07-15-2010 at 07:01 AM..
Reason: Code tags
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07-15-2010
