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Full Discussion: Check if the value is Number
Top Forums Shell Programming and Scripting Check if the value is Number Post 302435770 by radoulov on Thursday 8th of July 2010 07:28:22 AM
Old 07-08-2010
Code:
% cat infile 
123
234
23e
234.456
234.876e
345.00
% perl '-MScalar::Util qw(looks_like_number)' -F, -lne'
    print "$_ doesn\47t look like number!" unless looks_like_number $_
    ' infile
23e doesn't look like number!
234.876e doesn't look like number!

 

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NUMFMT_PARSE(3) 							 1							   NUMFMT_PARSE(3)

NumberFormatter::parse - Parse a number

	Object oriented style

SYNOPSIS
public mixed NumberFormatter::parse (string $value, [int $type], [int &$position]) DESCRIPTION
Procedural style mixed numfmt_parse (NumberFormatter $fmt, string $value, [int $type], [int &$position]) Parse a string into a number using the current formatter rules. PARAMETERS
o $fmt -NumberFormatter object. o $type - The formatting type to use. By default, NumberFormatter::TYPE_DOUBLE is used. o $position - Offset in the string at which to begin parsing. On return, this value will hold the offset at which parsing ended. RETURN VALUES
The value of the parsed number or FALSE on error. EXAMPLES
Example #1 numfmt_parse(3) example <?php $fmt = numfmt_create( 'de_DE', NumberFormatter::DECIMAL ); $num = "1.234.567,891"; echo numfmt_parse($fmt, $num)." "; echo numfmt_parse($fmt, $num, NumberFormatter::TYPE_INT32)." "; ?> Example #2 OO example <?php $fmt = new NumberFormatter( 'de_DE', NumberFormatter::DECIMAL ); $num = "1.234.567,891"; echo $fmt->parse($num)." "; echo $fmt->parse($num, NumberFormatter::TYPE_INT32)." "; ?> The above example will output: 1234567.891 1234567 SEE ALSO
numfmt_get_error_code(3), numfmt_format(3), numfmt_parse_currency(3). PHP Documentation Group NUMFMT_PARSE(3)
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