Hello
I am executing the following script
nawk 'NR == 1 || substr($0,63,5) ~ /H... / && \
_++ == 2 { fn && close(fn); fn = "part_" ++c; _ = 1 }
{ print > fn }' sample.dat
When i execute as it is it is executing fine. but when i execute the whole script as a single line like below
... (2 Replies)
I am executing the below in telnet
#!/usr/bin/ksh
File1=simple.txt # The file to check
LogFile=simple.log # The log file
DelayMax=30 # Timeout delay
Tolerance=2
# BEGIN ##############################
while true
do
StampNow=$(date +%s)/60 # stamp in minutes
... (3 Replies)
Hi ,
I m getting an error after executing the script.
My script.
Script is used to find out the date on 8 different machines(mentioned in SERVERNAMES file).
I have added public key to avoid ssh password and ssh without password working fine.
#!/bin/sh
fn_VMFind()
{
Date=`ssh -t... (5 Replies)
Hi
Please assist. Im getting an error while execuing the script name d "cdsnd.basel.cd_new
" as siiadm user. Thanks.
siiadm> ls -l
total 64
-rwxr-xr-x 1 siiadm sboadm 1004 Sep 17 2008 cdsnd.basel.cd
-rwxr-xr-x 1 siiadm sapsys 998 Nov 16 09:14 cdsnd.basel.cd_new... (1 Reply)
Hi,
I am not able to figure out what the problem is:
getting the following error
sqltst.sh: 1: not found
here is the script
#!/bin/sh
. /home/dev1/.profile
. /home/dev1/.infenv
`sqlplus -s $REPDB_LOGON << EOF
SET SERVEROUT ON
SET FEEDBACK OFF
SET HEADING OFF
SET TRIMSPOOL... (4 Replies)
hi all,
i am getting libssh2 error while executing script in RHEL 6, when i locate that file its not there below is the ouput of this
# locate libssh2_agent_init
# cat /etc/issue
Red Hat Enterprise Linux Server release 6.1 (Santiago)
Kernel \r on an \m
how do i resolve this issue, i... (1 Reply)
I have the following script test.sh owned by dwdev account and group dwdev, the permissions on the script are as follows.
-rw-r-x--- 1 dwdev dwdev 279 Sep 17 13:19 test.sh
Groups:
cat /etc/group | grep dwdev
dwdev:x:704:dwdev
dwgroup:x:725:dwdev
writers:x:726:dwdev
User:
cat /etc/passwd |... (3 Replies)
Hi,
I wrote this script to test if the output for DIR1 and DIR2 comes out as I want :
#!/bin/bash
DAY=$(date +%d)
MONTH=$(date +%b)
YEAR=$(date +%Y)
DIR1=$($MONTH$YEAR"_Blast_BC01")
DIR2=$($MONTH$YEAR"_Blast_BC15")
echo $DIR1
echo $DIR2
This is the output I want for echo $DIR1 ... (12 Replies)
Discussion started by: anaigini45
12 Replies
LEARN ABOUT PHP
eval
EVAL(3) 1 EVAL(3)eval - Evaluate a string as PHP codeSYNOPSIS
mixed eval (string $code)
DESCRIPTION
Evaluates the given $code as PHP.
Caution
The eval(3) language construct is very dangerous because it allows execution of arbitrary PHP code. Its use thus is discouraged.
If you have carefully verified that there is no other option than to use this construct, pay special attention not to pass any user
provided data into it without properly validating it beforehand.
PARAMETERS
o $code
- Valid PHP code to be evaluated. The code mustn't be wrapped in opening and closing PHP tags, i.e. 'echo "Hi!";' must be passed
instead of '<? echo "Hi!"; >'. It is still possible to leave and reenter PHP mode though using the appropriate PHP tags, e.g.
'echo "In PHP mode!"; ?>In HTML mode!<? echo "Back in PHP mode!";'. Apart from that the passed code must be valid PHP. This
includes that all statements must be properly terminated using a semicolon. 'echo "Hi!"' for example will cause a parse error,
whereas 'echo "Hi!";' will work. A return statement will immediately terminate the evaluation of the code. The code will be exe-
cuted in the scope of the code calling eval(3). Thus any variables defined or changed in the eval(3) call will remain visible
after it terminates.
RETURN VALUES eval(3) returns NULL unless return is called in the evaluated code, in which case the value passed to return is returned. If there is a
parse error in the evaluated code, eval(3) returns FALSE and execution of the following code continues normally. It is not possible to
catch a parse error in eval(3) using set_error_handler(3).
EXAMPLES
Example #1
eval(3) example - simple text merge
<?php
$string = 'cup';
$name = 'coffee';
$str = 'This is a $string with my $name in it.';
echo $str. "
";
eval("$str = "$str";");
echo $str. "
";
?>
The above example will output:
This is a $string with my $name in it.
This is a cup with my coffee in it.
NOTES
Note
Because this is a language construct and not a function, it cannot be called using variable functions.
Tip
As with anything that outputs its result directly to the browser, the output-control functions can be used to capture the output of
this function, and save it in a string (for example).
Note
In case of a fatal error in the evaluated code, the whole script exits.
SEE ALSO call_user_func(3).
PHP Documentation Group EVAL(3)