using awk to print date Post: 302432254

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

How do I get awk to print a " in it's print part?

The line is simple, use " '{ print $1"]"$2"\"$3THE " NEEDS TO GO HERE$4 }' I've tried \", "\, ^" and '"" but none of it works. What am I missing? Putting in the [ between $1 and $2 works fine, I just need to do the same with a ". Thanks.

2. Shell Programming and Scripting

how to print date using ftp commands

Hi friends sftpCmd.txt ----------------- !echo "Getting files from sftp" !echo "----------------" cd /home/msgGoogle/PLATFORM/PROD/MIMUS/outbound/ARCHIVE/invsnap !echo "folder created" !date mget ???050108*.txt output !echo "------------------" !echo "Completed : " !echo...

3. UNIX for Dummies Questions & Answers

awk to print current date?

List, I want to print the first line of my text file (say "me you"), preceded by the current date/time. Something like (pseudo code): awk '{print date,$1}' I don't have a lot of awk knowledge (understatement), so forgive me if the answer is obvious...

4. UNIX and Linux Applications

Print date at END clause of AWK

Hi to all! I 'm new in unix programing so... may be I decided a wrong tool to solve the problem but anyway... all road goes to rome jajaja. My question is: There is any way to print date at the END clause of an AWK script. I mean, I'm writing a tool with AWK and the results are redirected to a...

5. Shell Programming and Scripting

print out date of files last created??

Hello everyone, I have this script here: use Time::Local; opendir (D, $ARGV) or die "Cant open"; foreach $file (readdir D) { $path = "$ARGV/$file"; next if ! -T $path; $last_mod = (stat $path); ($sec,$min,$hour,$mday,$mon,$year,$wday) = localtime ($last_mod); printf "%-15s:...

6. Shell Programming and Scripting

Find and print specific date with awk

hi all I would like to help me find the problem with this script to find and print to the screen a specific date of a log file that I have on my server, the date it is received as the first argument in the script $ 1 Here I show you a few lines that made the idea of my log file: ****...

7. Shell Programming and Scripting

Find week of the year for given date using date command inside awk

Hi all, Need an urgent help on the below scenario. script: awk -F"," 'BEGIN { #some variable assignment} { #some calculation and put values in array} END { year=#getting it from array and assume this will be 2014 month=#getting it from array and this will be 05 date=#...

8. UNIX for Dummies Questions & Answers

Print start date to end date, given $1 & $2 in ksh

Dear all, I have an user passing 2 parameter 31/03/2015 and 02/04/2015 to a ksh script. How to print the start date to end date. Expected output is : 31/03/2015 01/04/2015 02/04/2015 Note : 1. Im using aix and ksh 2. I have tried to convert the given input into a date, didnt...

9. Red Hat

Print Date when Broken Pipe happens

Hi all, as i have multiple broken pipes on ssh sessions, i need to find out after how much time it happens, ssh root@testServer root@testServer's password: ssh:notty Last login: Thu Apr 6 06:41:16 2017 from 10.10.10.2 # but when broke pipe happen i don't have any idea after how much...

10. HP-UX

awk command in hp UNIX subtract 30 days automatically from current date without date illegal option

current date command runs well awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat subtract 30 days fails awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat awk command in hp unix subtract 30 days automatically from current date without date illegal option error...

LEARN ABOUT DEBIAN

iso8601

PACEMAKER(8)						  System Administration Utilities					      PACEMAKER(8)

NAME

       Pacemaker - Part of the Pacemaker cluster resource manager

SYNOPSIS

       iso8601 command [output modifier]

DESCRIPTION

       iso8601 - Display and parse ISO8601 dates and times

OPTIONS

       -?, --help
	      This text

       -$, --version
	      Version information

       -V, --verbose
	      Increase debug output

   Commands:
       -n, --now
	      Display the current date/time

       -d, --date=value
	      Parse an ISO8601 date/time.  Eg. '2005-01-20 00:30:00 +01:00' or '2005-040'

       -p, --period=value
	      Parse an ISO8601 date/time with interval/period (wth start time).  Eg. '2005-040/2005-043'

       -D, --duration=value
	      Parse an ISO8601 date/time with duration (wth start time). Eg. '2005-040/P1M'

   Output Modifiers:
       -L, --local
	      Show result as a 'local' date/time

       -O, --ordinal
	      Show result as an 'ordinal' date/time

       -W, --week
	      Show result as an 'calendar week' date/time

       For more information on the ISO8601 standard, see: http://en.wikipedia.org/wiki/ISO_8601

AUTHOR

       Written by Andrew Beekhof

REPORTING BUGS

       Report bugs to pacemaker@oss.clusterlabs.org

Pacemaker 1.1.7 						    April 2012							      PACEMAKER(8)

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

How do I get awk to print a " in it's print part?

Discussion started by: LordJezo

2. Shell Programming and Scripting

how to print date using ftp commands

Discussion started by: kittusri9

3. UNIX for Dummies Questions & Answers

awk to print current date?

Discussion started by: philipz

4. UNIX and Linux Applications

Print date at END clause of AWK

Discussion started by: fmeriles