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Top Forums Shell Programming and Scripting How to replace characters with random characters Post 302432032 by hellocatfood on Wednesday 23rd of June 2010 03:40:39 PM
Old 06-23-2010
How to replace characters with random characters

I've got a file (numbers.txt) filled with numbers and I want to replace each one of those numbers with a new random number between 0 and 9. This is my script so far:

Code:
#!/bin/bash
rand=$(($RANDOM % 9))
sed -i s/[0-9]/$rand/g numbers.txt

The problem that I have is that it replaces each number with just one random number (for example 82197 would just become 33333). Is there any way that I can get the script to replace each number with a random number?
 

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rand(3C)																  rand(3C)

NAME
rand(), rand_r(), srand() - simple random-number generator SYNOPSIS
DESCRIPTION
uses a multiplicative, congruential, random-number generator with period 2^32 that returns successive pseudo-random numbers in the range from 0 to 2^15-1. can be called at any time to reset the random-number generator to a random starting point. The generator is initially seeded with a value of 1. returns a random number at the address pointed to by the randval parameter. The seed parameter can be set at any time to start the random- number generator at an arbitrary point. Note The spectral properties of leave a great deal to be desired. provides a much better, though more elaborate, random-number generator (see drand48(3C)). RETURN VALUE
If seed or randval is NULL, returns 0. Otherwise, returns a psuedo-random integer. EXAMPLES
The following: int x, y; srand(10); x = rand(); y = rand(); would produce the same results as: int x, y, s = 10; x=rand_r(&s); y=rand_r(&s); WARNINGS
Users of should note that rand_r() now conforms with POSIX.1c. The old prototype of is supported for compatibility with existing DCE applications only. SEE ALSO
drand48(3C), random(3M), thread_safety(5), random(7). STANDARDS CONFORMANCE
rand(3C)
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