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Top Forums Shell Programming and Scripting Help to generate date from day of the year Post 302427297 by cfajohnson on Friday 4th of June 2010 01:25:06 PM
Old 06-04-2010
Quote:
Originally Posted by anchal_khare
Code:
-bash-3.1$ str=2005029
-bash-3.1$ yr=$(echo $str | cut -c3-4)
-bash-3.1$ dd=$(echo $str | cut -c6-7)


There's no need for an external command (cut):
Code:
str=2005329
yr=${str%???}
dd=${str#????}

 

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CAL_TO_JD(3)								 1							      CAL_TO_JD(3)

cal_to_jd - Converts from a supported calendar to Julian Day Count

SYNOPSIS
int cal_to_jd (int $calendar, int $month, int $day, int $year) DESCRIPTION
cal_to_jd(3) calculates the Julian day count for a date in the specified $calendar. Supported $calendars are CAL_GREGORIAN, CAL_JULIAN, CAL_JEWISH and CAL_FRENCH. PARAMETERS
o $calendar - Calendar to convert from, one of CAL_GREGORIAN, CAL_JULIAN, CAL_JEWISH or CAL_FRENCH. o $month - The month as a number, the valid range depends on the $calendar o $day - The day as a number, the valid range depends on the $calendar o $year - The year as a number, the valid range depends on the $calendar RETURN VALUES
A Julian Day number. SEE ALSO
cal_from_jd(3), frenchtojd(3), gregoriantojd(3), jewishtojd(3), juliantojd(3), unixtojd(3). PHP Documentation Group CAL_TO_JD(3)
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