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Top Forums Shell Programming and Scripting NULL in between, at begining or at end of line - convert to space Post 302427114 by Amit.Sagpariya on Friday 4th of June 2010 02:26:20 AM
Old 06-04-2010
NULL in between, at begining or at end of line - convert to space

How to replace null with space?

I want to make each line with 80 characters. If any line contains only 5 characters and remaining is null, then i want to make it as 80 characrets where 5 is original characters and remaining 75 characters will be null..


NULL can come in between the line, at begining the line or at end of line.

I have tried using
Code:
 
 tr '\0' '\40' < inputfile >> outputfile

But it did not work... can somebody help me.
 

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strncpy(9r)															       strncpy(9r)

NAME
strncpy - General: Copies a null-terminated character string with a specified limit SYNOPSIS
char * strncpy( char *s1, char *s2, int n ); ARGUMENTS
Specifies a pointer to a buffer of at least n bytes. Specifies a pointer to a string (an array of characters terminated by a null charac- ter). Specifies the number of characters to be copied. DESCRIPTION
The strncpy routine copies string s2 to buffer s1. The routine stops copying after it copies a null character or n characters, whichever comes first. If the length of s2 as determined by the null character is less than n, the routine pads s1 with null characters. RETURN VALUES
The strncpy routine returns a pointer to /NULL at the end of the first string (or to the location following the last copied character if there is no NULL). The copied string will not be null terminated if the length of s2 is n characters or more. SEE ALSO
Routines: bcopy(9r), blkclr(9r), copystr(9r), ovbcopy(9r), strcpy(9r) strncpy(9r)
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