NULL in between, at begining or at end of line - convert to space
How to replace null with space?
I want to make each line with 80 characters. If any line contains only 5 characters and remaining is null, then i want to make it as 80 characrets where 5 is original characters and remaining 75 characters will be null..
NULL can come in between the line, at begining the line or at end of line.
I have tried using
But it did not work... can somebody help me.
what can I use ??
In vi, I can use :set list <-- and see end of line $.. or use cat -A but I am wondering if there is command or program that allows me to see all the hidden characters( space, tab and etc)
Please help
thanks. (3 Replies)
How to convert ^M appearing at end of line to unix newline?
As I have tried with ^M in 'tr' it replaced ^ to a newline.
Thanks in advance. (21 Replies)
cat file1|while read i
do
echo "$i"|wc
done
with this command the space in the end of the line not considered
how can solve that
for example:
read h
"hgyr "
echo "$h"|wc
4 (2 Replies)
Hi All,
below is my data file
file.txt
$$0 ServerA LAN1 AAA IT01 04/30/2008 09:16:26
$$0 ServerB LAN1 AAA IT02 04/30/2008 09:16:26
here $ is a blank space
how to delete first 2 blank spaces in a file. (4 Replies)
Hi !
I'm rather new with sed ... learned a lot already by googling etc ...
The following script should replace all spaces and ends-of-lines with "something (see below).
#!/bin/bash
i=0
while read line
do
fam="H`printf "%06d" $i`"
echo $line | sed -e 's//\t'$fam'\n/g'
i=$(($i+1))... (7 Replies)
for eg:
i have i/p file as:
================
i
wnt
to
change end of line
=================
my require ouput is like:
i wnt to change end of line
==================== (7 Replies)
I have a file with hundreds of records and I need to find those records that have three digits at the beginning and the same three digits at the end.
$GREP '\(\)\(\)\(\)\3\2\1'I
believe this is part of the script but I am not sure how to compare these 3 digits with the 3 digits at the end of... (2 Replies)
Hello,
I would like to convert a list of rows to a space separated line. Any ideas?
Input file:
"Administration Tools"
"Design Suite"
"Dial-up Networking Support"
"Editors"
desired output
"Administration Tools" "Design Suite" "Dial-up Networking Support" "Editors"
Thanks,... (4 Replies)
Hi,
Since today, with csh or tcsh, if I do 'ls files* > list',
every lines end with an extra space!
What happenned?
What can I do to go back when there was no extra space?
If I change to bash, there's no extra space.
Thanks,
Patrick
---------- Post updated at 03:19 PM... (1 Reply)
Discussion started by: trogne
1 Replies
LEARN ABOUT OSF1
strncpy
strncpy(9r)strncpy(9r)NAME
strncpy - General: Copies a null-terminated character string with a specified limit
SYNOPSIS
char * strncpy(
char *s1,
char *s2,
int n );
ARGUMENTS
Specifies a pointer to a buffer of at least n bytes. Specifies a pointer to a string (an array of characters terminated by a null charac-
ter). Specifies the number of characters to be copied.
DESCRIPTION
The strncpy routine copies string s2 to buffer s1. The routine stops copying after it copies a null character or n characters, whichever
comes first. If the length of s2 as determined by the null character is less than n, the routine pads s1 with null characters.
RETURN VALUES
The strncpy routine returns a pointer to /NULL at the end of the first string (or to the location following the last copied character if
there is no NULL). The copied string will not be null terminated if the length of s2 is n characters or more.
SEE ALSO
Routines: bcopy(9r), blkclr(9r), copystr(9r), ovbcopy(9r), strcpy(9r)strncpy(9r)