Can you please try this code alone and let me know what is its ouptut:
If it works then there's probably another error in you script (please post your complete script in this case), else you work with a non-posix sh or something.
Hi all,
I have a variable with date as 20080831 . Now I want to increment it as 20080901 and so on.Is there any command for this. Please help me.
thanks
rameez (1 Reply)
Here is my code:
int startingPort = 200;
string tempPort;
stringstream out;
out<<startingPort;
tempPort = out.str(); //tempPort carries startingPort in string format
//convert tempPort to *char - currentPort going to be passed into getaddrinfo()
char currentPort;... (10 Replies)
Hi All,
Iam trying to increment a variable
Following is the code
#!/usr/bin/ksh
i=1;
i='expr $i+1';
echo $i;
Output:
expr $i+1
not able to understand why its happening in that way
i was expecting result as 2... if the above method is worng .. can you help how i can get... (3 Replies)
1. The problem statement, all variables and given/known data:
Variable is resetting to 0 after incrementing in while loop
My bit of scripting displays the current users logged in the machine.
Then it reads in a specific username and displays the processes for that user.
The portion that I... (3 Replies)
Hi,
I am using BASH. I have encountered a situation where the following is necessary (but I am not sure how to do it):
#Define multiple arrays, whose names only differ by a number:
ARRAY_1=(1 2 3)
ARRAY_2=(4 5 6)
ARRAY_3=(7 8 9)
#Define ARRAY_AMOUNT, the number of arrays. In this case... (1 Reply)
Hi,
want to increment a variable in a for loop like this:
for (( c=$total-1; c>=0; c-- ))
do
if ;
then
maximo=$valores
fi
done
But it gives the error:
No such file or directory
How can i do this only incrementing the c variable?
Thanks (8 Replies)
Hi,
I am able to login using su - or su directly ,
# prompt is coming, it doesnt ask for password.
any normal user on aix system is login using su - or su .
Please suggest where to change the configuration
direct root login is disabled in /etc/ssh/sshd_config file. (0 Replies)
Hello folks.
I am trying to increment my variable names to match a counter that is to be used later on...
Basically, i have a for loop that lists directories (for example TEST_OS DVP_OS PROD_OS ) but this loop is not static, it may contain 3 directory once and the next run 5 directories.
I... (6 Replies)
This is part of a larger script where I need to pass only 1 line of a file to the script, based on a variable and not a direct reference.
As part of a for loop :
# for((line=0;line<50;line++)); do
# awk ‘NR==$line' PhraseList.txt; done
... (5 Replies)
Discussion started by: Seth
5 Replies
LEARN ABOUT CENTOS
shell-quote
SHELL-QUOTE(1) User Contributed Perl Documentation SHELL-QUOTE(1)NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS --debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.16.3 2010-06-11 SHELL-QUOTE(1)