Hi Experts,
I am adding a column of numbers with awk , however not getting correct output:
# awk '{sum+=$1} END {print sum}' datafile
2.15291e+06
How can I getthe output like : 2152910
Thank you..
# awk '{sum+=$1} END {print sum}' datafile
2.15079e+06 (3 Replies)
I have a file which has following contents
usmtnz-dinfsi19
62
61
18400
18800
99.7
usmtnz-dinfsi19
62
61
18400
18800
99.7
i want the o/p to be like
date (7 Replies)
when i run the following command
db2 list tablespaces
Tablespaces for Current Database
Tablespace ID = 0
Name = SYSCATSPACE
State = 0x0000
Tablespace ID ... (3 Replies)
I have a script that reaches out to several systems and pulls back infomation in serveral files. I would like to take the infomation returned and reformat it so I can export it to excel.
Below is current output:
File1:item1:abc=1
File1:item2:efg
File2:item1:ab=1
File2:item2:efg... (3 Replies)
Hi,
i have a file input.txt
Continent North America
Country USA Capital Washington D.C.
Country Canada Capital Ottawa
Continent South America
Country Argentina Capital Buenos Aires
Country Brazil Capital Brasília
Coutry Colombia Capital Bogotá
and i want to get an output.txt
... (3 Replies)
I have below date format in a CSV file. (dd/mm/yyyy)
Ex Input:
9/8/2013
Need to convert it into below format (yyyymmdd ) and redirect to new file.
Ex Output:
20130809
How do I use awk here to change the format and if leading 0 (zero) is not then add it.
Please help. Thanks. (8 Replies)
Basically I am trying to run a standard output of IP address with a port number into another command but I need to change it from.
74.125.224.194.80 into 74.125.224.194:80
One command wants a period before the port the subsequent one wants a colon.
So is there anyway I can feed... (3 Replies)
Hi,
I have a file where I need to change the date format on the nth field from DD-MM-YYYY to YYYY-MM-DD so I can accurately sort the record by dates
From regex - Use sed or awk to fix date format - Stack Overflow, I found an example using nawk.
Test run as below:
$: cat xyz.txt
A ... (2 Replies)
Discussion started by: newbie_01
2 Replies
LEARN ABOUT DEBIAN
shtool-path
SHTOOL-PATH.TMP(1) GNU Portable Shell Tool SHTOOL-PATH.TMP(1)NAME
shtool-path - GNU shtool command dealing with shell path variables
SYNOPSIS
shtool path [-s|--suppress] [-r|--reverse] [-d|--dirname] [-b|--basename] [-m|--magic] [-p|--path path] str [str ...]
DESCRIPTION
This command deals with shell $PATH variables. It can find a program through one or more filenames given by one or more str arguments. It
prints the absolute filesystem path to the program displayed on "stdout" plus an exit code of 0 if it was really found.
OPTIONS
The following command line options are available.
-s, --suppress
Supress output. Useful to only test whether a program exists with the help of the return code.
-r, --reverse
Transform a forward path to a subdirectory into a reverse path.
-d, --dirname
Output the directory name of str.
-b, --basename
Output the base name of str.
-m, --magic
Enable advanced magic search for ""perl"" and ""cpp"".
-p, --path path
Search in path. Default is to search in $PATH.
EXAMPLE
# shell script
awk=`shtool path -p "${PATH}:." gawk nawk awk`
perl=`shtool path -m perl`
cpp=`shtool path -m cpp`
revpath=`shtool path -r path/to/subdir`
HISTORY
The GNU shtool path command was originally written by Ralf S. Engelschall <rse@engelschall.com> in 1998 for Apache. It was later taken
over into GNU shtool.
SEE ALSO shtool(1), which(1).
18-Jul-2008 shtool 2.0.8 SHTOOL-PATH.TMP(1)