Hi, I'm new with Unix, I'm trying to get a last day of previous month with this format: %b %d %Y (example: Feb 25 2008).
Here is what I have so far.
#!/bin/ksh
cur_month=`date +%m`
cur_year=`date +%Y`
prev_month=$(($cur_month-1))
# Check to see if this is January
if
then
... (11 Replies)
Hello,
I wanted to display the month for previous day date. Like, today date is 18-Nov-2008. So the previous date is 17-Nov-2008. The output should be November.
If the today date is 1-DEC-2008, then output should be NOVEMBER.
If the today date is 1-JAN-2008, then output should be DECEMBER.... (4 Replies)
Hello,
I'm new to shell scripting.
We've develop a script which will grep a file on the search criteria, MON (Jan/Feb/Mar/etc). But we should set this sript in cron which will run on every first day of the month. The problem I'm having is, when I run the script, it is displaying the contents of... (7 Replies)
Hi All,
I need to find the previous month last day minus one day, using shell script. Can you guys help me to do this.
My Requirment is as below:
Input for me will be 2000909(YYYYMM)
I need the previous months last day minus 1 day timestamp. That is i need 2000908 months last day minus ... (3 Replies)
Hi,
On any given day, I want to capture the month that has gone by - said otherwise, how do I capture last month?
expr date '+%m' - 1
Above expression is giving error.
Please advise
thanks
---------- Post updated at 09:28 AM ---------- Previous update was at 09:11 AM... (1 Reply)
Hi,
i unable to get the last month date in AIX.
current date - one month
Based on the forums tried but did not find the relevent information.
Any help grealy appriciated.
Thanks
Suri. (3 Replies)
Hi All,
I am using the below code to get the year and month from date:
Below gives output like 201212.
dt=`date '+%Y%m'`
how do i get the previous month value(ie: subtract 1 from date)
example output:
dt=201211
Please help. :confused: (3 Replies)
I have requirment to get last date of previous month and the first date of previous 4th month:
Example:
Current date: 20130320 (yyyymmdd)
Last date of previous month: 20130228 (yyyymmdd)
First date of previous 4th month: 20121101 (yyyymmdd)
In my shell --date, -d, -v switches are not... (3 Replies)
I am running a script in ksh to get the 2 months back date from system date.The below code is giving correct date output from putty command prompt.But while running the script is .ksh file it is giving the error below.Please suggest.
; d=a; y=a
m-=num
while(m < 1) {m+=12; y--}... (1 Reply)
Discussion started by: hini
1 Replies
LEARN ABOUT OPENSOLARIS
cal
cal(1) User Commands cal(1)NAME
cal - display a calendar
SYNOPSIS
cal [ [month] year]
DESCRIPTION
The cal utility writes a Gregorian calendar to standard output. If the year operand is specified, a calendar for that year is written. If
no operands are specified, a calendar for the current month is written.
OPERANDS
The following operands are supported:
month Specify the month to be displayed, represented as a decimal integer from 1 (January) to 12 (December). The default is the current
month.
year Specify the year for which the calendar is displayed, represented as a decimal integer from 1 to 9999. The default is the current
year.
ENVIRONMENT VARIABLES
See environ(5) for descriptions of the following environment variables that affect the execution of cal: LANG, LC_ALL, LC_CTYPE, LC_TIME,
LC_MESSAGES, and NLSPATH.
TZ Determine the timezone used to calculate the value of the current month.
EXIT STATUS
The following exit values are returned:
0 Successful completion.
>0 An error occurred.
ATTRIBUTES
See attributes(5) for descriptions of the following attributes:
+-----------------------------+-----------------------------+
| ATTRIBUTE TYPE | ATTRIBUTE VALUE |
+-----------------------------+-----------------------------+
|Availability |SUNWesu |
+-----------------------------+-----------------------------+
|Interface Stability |Standard |
+-----------------------------+-----------------------------+
SEE ALSO calendar(1), attributes(5), environ(5), standards(5)NOTES
An unusual calendar is printed for September 1752. That is the month 11 days were skipped to make up for lack of leap year adjustments. To
see this calendar, type:
cal 9 1752
The command cal 83 refers to the year 83, not 1983.
The year is always considered to start in January.
SunOS 5.11 1 Feb 1995 cal(1)