Say I do a date command and get the time from 15 minutes ago.
I have a text file with the date printed out every minute or so and I want to cut the file at the date stamp given to me by the 15 minute ago time stamp.
Is there an easy way to do this?
Example:
date +%M gives me 56
I... (2 Replies)
Let's say I have a line like that:
I want to cut out numbers between two $ including $s. The result should be like that:
I am so-newbei. I am non-stop reading about SED since yesterday and not a programmer. I know that it is a short period, thus maybe I had overlooked something. I... (4 Replies)
Hi,
I have text file which contains lines like :
a/a/a/a/.project
b/b/b/b/b/.project
c/c/c/.project
d/.project
e/e/e/e/.project
i want for all lines the last word .project should be removed and the file should look like :
a/a/a/a/
b/b/b/b/b/
c/c/c/
....
how to proceed... (7 Replies)
First I have to say thank you to this community and this forum. You helped me very much builing several useful scripts.
Now, I can't get a solution the following problem, I'm stuck somehow. Maybe someone has an idea.
In short, I dump a site via lynx and pipe the output in a file. I need to... (7 Replies)
Hi All,
I would like help with a script which can get rid of the first work of all lines in text file.
File 1
The name is Scott.
Output : name is Scott
---------- Post updated at 02:38 PM ---------- Previous update was at 02:37 PM ----------
Hi ALL
There is typo error in... (3 Replies)
Hi,
I got a line of text which has spaces in between and it is a long stream of characters. I want to extract the text from certain position. Below is the line and I want to take out 3 characters from 86 to 88 character position. In this line space is also a character. However when using cut... (5 Replies)
Looking for some help on using awk and cut
I have a text file that has fixed information and want to write a script that will prompt the user for an account to search for and pint the output
The sample line that has the key information looks like this:
Statement to: ... (5 Replies)
I have a file that i want to take only the first part of it and discard the rest, to be accurate,I need the first 137097 lines but I cant use split because I dont have enough space on my disck. I need sth to cut the file in its place (3 Replies)
Hello Friends,
I am stuck with the below problem.Any help will be appreciated.
I have a file which has say 100 lines.
On the second last line I have a line from which i want to remove certain characters..
e.g
CAST(CAST( A as varchar(50)) || ',' ||
CAST(CAST( B as varchar(50)) || ',' ||... (8 Replies)
Discussion started by: vital_parsley
8 Replies
LEARN ABOUT OSX
cut
CUT(1) BSD General Commands Manual CUT(1)NAME
cut -- cut out selected portions of each line of a file
SYNOPSIS
cut -b list [-n] [file ...]
cut -c list [file ...]
cut -f list [-d delim] [-s] [file ...]
DESCRIPTION
The cut utility cuts out selected portions of each line (as specified by list) from each file and writes them to the standard output. If no
file arguments are specified, or a file argument is a single dash ('-'), cut reads from the standard input. The items specified by list can
be in terms of column position or in terms of fields delimited by a special character. Column numbering starts from 1.
The list option argument is a comma or whitespace separated set of numbers and/or number ranges. Number ranges consist of a number, a dash
('-'), and a second number and select the fields or columns from the first number to the second, inclusive. Numbers or number ranges may be
preceded by a dash, which selects all fields or columns from 1 to the last number. Numbers or number ranges may be followed by a dash, which
selects all fields or columns from the last number to the end of the line. Numbers and number ranges may be repeated, overlapping, and in
any order. If a field or column is specified multiple times, it will appear only once in the output. It is not an error to select fields or
columns not present in the input line.
The options are as follows:
-b list
The list specifies byte positions.
-c list
The list specifies character positions.
-d delim
Use delim as the field delimiter character instead of the tab character.
-f list
The list specifies fields, separated in the input by the field delimiter character (see the -d option.) Output fields are separated
by a single occurrence of the field delimiter character.
-n Do not split multi-byte characters. Characters will only be output if at least one byte is selected, and, after a prefix of zero or
more unselected bytes, the rest of the bytes that form the character are selected.
-s Suppress lines with no field delimiter characters. Unless specified, lines with no delimiters are passed through unmodified.
ENVIRONMENT
The LANG, LC_ALL and LC_CTYPE environment variables affect the execution of cut as described in environ(7).
EXIT STATUS
The cut utility exits 0 on success, and >0 if an error occurs.
EXAMPLES
Extract users' login names and shells from the system passwd(5) file as ``name:shell'' pairs:
cut -d : -f 1,7 /etc/passwd
Show the names and login times of the currently logged in users:
who | cut -c 1-16,26-38
SEE ALSO colrm(1), paste(1)STANDARDS
The cut utility conforms to IEEE Std 1003.2-1992 (``POSIX.2'').
HISTORY
A cut command appeared in AT&T System III UNIX.
BSD December 21, 2006 BSD