The statement is poorly phrased, btw., because it is asking for troubles: the asterisk ("*") has a special meaning to the shell and to protect such special characters from being interpreted one should cover them in quotes:
Code:
DIR="$1/*"
It is not necessary to quote an assignment unless it contains literal whitespace.
Quote:
Furthermore, when using variable-names without spaces surrounding them it is a wise precaution to explicitly mark what belongs to the variable identifier and what doesn't:
Code:
DIR="${1}/*"
There's no point to using braces when the name is followed by a character that cannot be contained in a variable name.
Quote:
In your case this makes no difference, but consider:
Code:
a="blabla"
b="$ab" # appending "b" will not work, because a variable named "ab" is expected
echo "$b"
b="${a}b" # this will work
echo "$b"
I hope this helps.
bakunin
Last edited by cfajohnson; 04-20-2010 at 02:54 AM..
I'm writing a bash script to search the contents of a postfix log. To keep the script's output readable (since multiple lines from the log file need to be echo'ed) I am setting the IFS variable to an empty string so that the line breaks in my grep results are preserved. I am storing the results... (4 Replies)
Hi All,
I need to pass a variable to perl script from bash script, where in perl i am using if condition. Here is the cmd what i am using in perl
FROM_DATE="06/05/2008"
TO_DATE="07/05/2008"
"perl -ne ' print if ( $_ >="$FROM_DATE" && $_ <= "$TO_DATE" ) ' filename"
filename has... (10 Replies)
Hi,
I use AIX (ksh) and Linux (bash) servers. I'm trying to do scripts to will run in both ksh and bash, and most of the time it works. But this time I don't get it in bash (I'm more familar in ksh).
The goal of my script if to read a "config file" (like "ini" file), and make various report.... (2 Replies)
Hi, I've been running code which very frequently calls books.csv. e.g:
grep -i horror books.csv > tempExcept, I'm trying to move away from using temporary files or frequently calling books.csv to improve efficiency. So I tried something like
bookfile=$(cat books.csv)
grep -i horror... (4 Replies)
have a script that calls child scripts depending on conditions. All of the child scripts source in a common file that contains shared functions.
At the moment each script has to source this file itself, is there a way for the master script to automagically source the file for them?
For... (3 Replies)
Hello,
The task is quite simple. I need to initialise а string variable and assign to it a very long value. For the reason of readability I want to devide this long value into equal parts and place each part at a separate line.
For instance, I have -
... (1 Reply)
Suppose I have a file named Stuff in the same directory as my script. Does the following assign the file Stuff to a variable?
Var="Stuff"
Why doesn't this just assign the string Stuff? Or rather how would I assign the string Stuff to a variable in this situation?
Also, what exactly is... (3 Replies)
while i've used arrays to work with variables, i've never used them to loop through a set of strings and wanted to ask the community for some feedback or assistance.
let me be specific. here's my code:
# URL port Variables
port2195=`nc -z $url2195 2195`
port2196=`nc -z $url2196 2196`... (5 Replies)
Hello,
I am new to Linux and studying to become a Unix System Admin. I am taking a course in which I was practicing creating a bash script to ping a particular IP address. The script can be found below:
#/bin/bash
echo "Enter the IP address"
read ip
if
then
ping -c 1 $ip
if ;... (3 Replies)
Hello All,
I have a file of ip addresses called activeips.txt
What I'm trying to do is run a simple bash script that has a loop in it. The loop is a cat of the IP addresses in the file.
The goal is to run 2 nmap commands to give me outputs where each address in the list has an OS... (11 Replies)
Discussion started by: Dirk_Pitt
11 Replies
LEARN ABOUT LINUX
bashbug
BASHBUG(1) bashbug BASHBUG(1)NAME
bashbug - report a bug in bash
SYNOPSIS
bashbug [--help] [--version] [bug-report-email-addresses]
DESCRIPTION
bashbug is a utility for reporting bugs in Bash to the maintainers.
bashbug will start up your preferred editor with a preformatted bug report template for you to fill in. Save the file and quit the editor
once you have completed the missing fields. bashbug will notify you of any problems with the report and ask for confirmation before
sending it. By default the bug report is mailed to both the GNU developers and the Debian Bash maintainers. The recipients can be changed
by giving a comma separated list of bug-report-email-addresses.
If you invoke bashbug by accident, just quit your editor. You will always be asked for confirmation before a bug report is sent.
OPTIONS --help
Show a brief usage message and exit.
--version
Show the version of bashbug and exit.
bug-report-email-addresses
Comma separated list of recipients' email addresses. By default the report is mailed to both the GNU developers and the Debian Bash
maintainers.
ENVIRONMENT
DEFEDITOR
Editor to use for editing the bug report.
EDITOR
Editor to use for editing the bug report (overridden by DEFEDITOR).
SEE ALSO bash(1), reportbug(1), update-alternatives(8) for preferred editor.
AUTHOR
This manual page was written by Christer Andersson <klamm@comhem.se> for the Debian project (but may be used by others).
GNU Bash 3.1 11 December 2007 BASHBUG(1)