Calling all experts:
When I ftp from Mainframe to unix server, the ftp message says fixed length 2060, but i lose trailing spaces.
I tried a solution i found here,
awk ' { printf("%-2060s\n",$0) } ' fname1 > fname2
works for small records but, err msg: string too long, for long records
... (1 Reply)
Hi,
i want to replace comma by space for specified field in record, i mean i want to replace the commas in the 4th field by space. and rest all is same throught the record.
the record is
16458,99,001,"RIMOUSKI, QC",418,"N",7,EST,EDT,902
16458,99,002,"CHANDLER,... (5 Replies)
Hi
I have a complex script which outputs a text file for loading into a db.
I now need to enhance this script do that I can issue an ‘lp' command
to show the count of the number of records in this file.
Can anybody give me the necessary syntax ? (2 Replies)
I have a loop like
while read i
do
echo "$i"
.
.
.
done < tms.txt
The tms.txt contians data like
2008-02-03 00:00:00
<space>00:00:00
.
.
.
2010-02-03 10:54:32 (2 Replies)
i have a find command piped to an awk script, I'm expecting it printing the matching record one time but it's doing it twice:
the following is my code:
find directoryname | awk 'BEGIN { FS="/" } /.*\.$/ || /.*\.$/ { printf "%s/%s\n", $(NF-1), $NF }
it gave me the correct output, but just... (2 Replies)
Hello Everyone,
I want to print out the records after and before a certain record. I am able to figure out how to print that particular record but not the ones before and after. Looking for some advice
Thank you (6 Replies)
Hi ,
I want to remove space from each record in one file My file is like
BUD, BDL
ABC, DDD, ABC
ABC, DDD, DDD, KKK
The o/p should be
BUD,BDL
ABC,DDD,ABC
ABC,DDD,DDD,KKK
Can any one help me regarding this? (9 Replies)
Hi! all
can any one tell me how to compare current record of column with next and previous record in awk without using array
my case is like this
input.txt
0 32
1 26
2 27
3 34
4 26
5 25
6 24
9 23
0 32
1 28
2 15
3 26
4 24 (7 Replies)
Hi,
I have file with thousands of lines somewhat similar to the below 6 lines
06MXXXXXXXXXXXXXXXX 0328 003529 J27300022 MICROSOFT *MSN
06<1 000000001344392 JPN151-85830 MSBILL.INFO F
06<A17087454000328651551 MSBILL.INFO ... (16 Replies)
Hi,
I have a backup report that unfortunately has some kind of hanging indent thing where the first line contains one column more than the others
I managed to get the output that I wanted using awk, but just wanting to know if there is short way of doing it using the same awk
Below is what... (2 Replies)
Discussion started by: newbie_01
2 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)