I wish to compute the number of dot chars in a string.
Example:
VAR="aaaa.bbbbb.cccc"
I try the shortest command to solve this test.
Thanks in advance for your help.
Regards,
Giovanni (7 Replies)
for example:
i hav a string like :
/rmsprd/arch01/rmsprd/rmsprdarch72736.log
how I can extract
my_num=72736?
I know I can
echo "/rmsprd/arch01/rmsprd/rmsprdarch72736.log" | tr "/" " " | awk '{ print $4 }' to get rmsprdarch72736.log (4 Replies)
Hi Guys,
I wand find and replace all Extended ASCII Codes from all my log files.
My Log files:
/home/Kalr/PPool/Output
i have logs file in sub dir.
/home/Kalr/PPool/Output/X
/home/Kalr/PPool/Output/Y
/home/Kalr/PPool/Output/Z
My Abc.log file input:
Extended ASCII Codes :–
... (4 Replies)
find /tmp -type f -mtime +180
I have this script get the list to clean up files older than 180 days under /tmp.
But, I want to make sure to grep only a type of files, which have only 6 character long.
....
LT3hqa dRMoya ... (16 Replies)
i have a script that scans a log file every 10 minutes. this script remembers the last line of the log and then uses it to continue monitoring the log when it runs again 10 minutes later.
the script searches the log for a string called MaxClients.
now, how can i make it so that when the... (7 Replies)
hello
how can i cont number of char with loop coomand?
i dont want to use wc or other special command
the script should check all word's char. one by one
also a counter can handle the number
As noted in other threads started today. This is not the correct forum for homework assignments. ... (2 Replies)
hi,
i having a file with | seperated in which i need to search char in 3rd column and replace with null. i need to replace only the coulmn where character occurs in 3rd field
for eg:
file1.txt
xx|yy|xx|12
output file:
xx|yy||12 (5 Replies)
I need to write a BASH script that takes a 2 character string and removes the second character if it is not a digit e.g.
If the string is numberical value >9 e.g. string1 = '34' then leave string1 = '34'.
However if the string is <10 e.g. string1 = '3X' then remove the second char (which... (7 Replies)
Hi
I want to use awk to match where field 3 contains a number within string - then print the line and just the number as a new field.
The source file is pipe delimited and looks something like
1|net|ABC Letr1|1530|||
1|net|EXP_1040 ABC|1121|||
1|net|EXP_TG1224|1122|||
1|net|R_North|1123|||... (5 Replies)
Discussion started by: Mudshark
5 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)