Sponsored Content
Full Discussion: Regular expression matching
Top Forums Shell Programming and Scripting Regular expression matching Post 302408638 by radoulov on Tuesday 30th of March 2010 06:08:21 AM
Old 03-30-2010
You can use expr:

Code:
expr "$var" : '^ *1 *$' >/dev/null && echo OK

 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Regular expression matching a new line

I have written a script to test some isdn links in my network and I am trying to format the output to be more readable. Each line of the output has a different number of digits as follows... Sitename , spid1 12345678901234 1234567890 1234567 , spid2 1234567890 1234567890 1234567 Sitename , ... (1 Reply)
Discussion started by: drheams
1 Replies

2. Programming

Regular Expression matching in PERL

I am trying to read a file and capture particular lines into different strings: LENGTH: Some Content here TEXT: Some Content Here COMMENT: Some Content Here I want to be able to get (LENGTH: .... ) into one array and so on... I'm trying to use PERL in slurp mode but for some reason... (8 Replies)
Discussion started by: Legend986
8 Replies

3. Shell Programming and Scripting

Help: Regular Expression for Negate Matching String

Hi guys, as per subject I am having problem with regular expressions. Example, if i got a string "javax.servlet.http.HttpServlet.service" that may occurred anywhere within a text file. How can I used the negate pattern matching of regular expression? I tried the below pattern but it... (4 Replies)
Discussion started by: DrivesMeCrazy
4 Replies

4. Shell Programming and Scripting

Regular expression matching in BASH (equivalent of =~ in Perl)

In Perl I can write a condition that evaluates a match expression like this: if ($foo =~ /^bar/) { do blah blah blah } How do I write this in shell? What I need to know is what operator do I use? The '=~' doesn't seem to fit. I've tried different operators, I browsed the man page for... (3 Replies)
Discussion started by: indiana_tas
3 Replies

5. Shell Programming and Scripting

Matching single quote in a regular expression

I trying to match the begining of the following line in a perl script with a regular expression. $ENV{'ORACLE_HOME'} I tried this regluar expession: /\$ENV\{\'ORACLE_HOME\'\}/ Instead of match, I got a blank prompt > It seems to be a problem with the single quote. If I take it... (11 Replies)
Discussion started by: JC9672
11 Replies

6. Shell Programming and Scripting

Hidden Characters in Regular Expression Matching Perl - Perl Newbie

I am completely new to perl programming. My father is helping me learn said programming language. However, I am stuck on one of the assignments he has given me, and I can't find very much help with it via google, either because I have a tiny attention span, or because I can be very very dense. ... (4 Replies)
Discussion started by: kittyluva2
4 Replies

7. Programming

Perl: How to read from a file, do regular expression and then replace the found regular expression

Hi all, How am I read a file, find the match regular expression and overwrite to the same files. open DESTINATION_FILE, "<tmptravl.dat" or die "tmptravl.dat"; open NEW_DESTINATION_FILE, ">new_tmptravl.dat" or die "new_tmptravl.dat"; while (<DESTINATION_FILE>) { # print... (1 Reply)
Discussion started by: jessy83
1 Replies

8. UNIX for Dummies Questions & Answers

delete lines matching a regular expression

I have a very large file (over 700 million lines) that has some lines that I need to delete. An example of 5 lines of the file: HS4_80:8:2303:19153:193032 153 k80:138891 HS4_80:8:2105:5544:43174 89 k88:81949 165 k88:81949 323 0 * = 323 0 ... (6 Replies)
Discussion started by: pathunkathunk
6 Replies

9. Shell Programming and Scripting

regular expression matching whole words

Hi Consider the file this is a good line when running grep '\b(good|great|excellent)\b' file5 I expect it to match the line but it doesn't... what am i doing wrong?? (ultimately this regex will be in a awk script- just using grep to test it) Thanks, Storms (5 Replies)
Discussion started by: Storms
5 Replies

10. UNIX for Advanced & Expert Users

sed: -e expression #1, char 0: no previous regular expression

Hello All, I'm trying to extract the lines between two consecutive elements of an array from a file. My array looks like: problem_arr=(PRS111 PRS213 PRS234) j=0 while } ] do k=`expr $j + 1` sed -n "/${problem_arr}/,/${problem_arr}/p" problemid.txt ---some operation goes... (11 Replies)
Discussion started by: InduInduIndu
11 Replies
expr(1B)					     SunOS/BSD Compatibility Package Commands						  expr(1B)

NAME
expr - evaluate arguments as a logical, arithmetic, or string expression SYNOPSIS
/usr/ucb/expr argument... DESCRIPTION
The expr utility evaluates expressions as specified by its arguments. After evaluation, the result is written on the standard output. Each token of the expression is a separate argument, so terms of the expression must be separated by blanks. Characters special to the shell must be escaped. Note: 0 is returned to indicate a zero value, rather than the null string. Strings containing blanks or other special characters should be quoted. Integer-valued arguments may be preceded by a unary minus sign. Internally, integers are treated as 32-bit, two's-complement numbers. The operators and keywords are listed below. Characters that need to be escaped are preceded by `'. The list is in order of increasing precedence, with equal precedence operators grouped within {} symbols. expr | expr Returns the evaluation of the first expr if it is neither NULL nor 0; otherwise, returns the evaluation of the second expr if it is not NULL; otherwise, 0. expr & expr Returns the first expr if neither expr is NULL or 0, otherwise returns 0. expr { =, , , <, <=, != } expr Returns the result of an integer comparison if both arguments are integers, otherwise returns the result of a lexical comparison. expr { +, - } expr Addition or subtraction of integer-valued arguments. expr { , /, % } expr Multiplication, division, or remainder of the integer-valued arguments. string : regular-expression match string regular-expression The two forms of the matching operator above are synonymous. The matching operators : and match compare the first argument with the second argument which must be a regular expression. Regular expression syntax is the same as that of regexp(5), except that all pat- terns are "anchored" (treated as if they begin with ^) and therefore ^ is not a special character, in that context. Normally, the matching operator returns the number of characters matched (0 on failure). Alternatively, the ... pattern symbols can be used to return a portion of the first argument. substr string integer-1 integer-2 Extracts the substring of string starting at position integer-1 and of length integer-2 characters. If integer-1 has a value greater than the length of string, expr returns a null string. If you try to extract more characters than there are in string, expr returns all the remaining characters from string. Beware of using negative values for either integer-1 or integer-2 as expr tends to run forever in these cases. index string character-list Reports the first position in string at which any one of the characters in character-list matches a character in string. length string Returns the length (that is, the number of characters) of string. ( expr ) Parentheses may be used for grouping. EXAMPLES
Example 1: Adding an integer to a shell variable Add 1 to the shell variable a. a='expr $a + 1' Example 2: Returning a path name segment Return the last segment of a path name (that is, the filename part). Watch out for / alone as an argument: expr will take it as the divi- sion operator (see BUGS below). # 'For $a equal to either "/usr/abc/file" or just "file"' expr $a : '.*/ $a Example 3: Using // characters to simplify the expression The addition of the // characters eliminates any ambiguity about the division operator and simplifies the whole expression. # A better representation of example 2. expr //$a : '.*/ Example 4: Returning the value of a variable Returns the number of characters in $VAR. expr $VAR : '.*' EXIT STATUS
expr returns the following exit codes: 0 If the expression is neither NULL nor 0. 1 If the expression is NULL or 0. 2 For invalid expressions. ATTRIBUTES
See attributes(5) for descriptions of the following attributes: +-----------------------------+-----------------------------+ | ATTRIBUTE TYPE | ATTRIBUTE VALUE | +-----------------------------+-----------------------------+ |Availability |SUNWscpu | +-----------------------------+-----------------------------+ SEE ALSO
sh(1), test(1), attributes(5), regexp(5) DIAGNOSTICS
syntax error for operator/operand errors non-numeric argument if arithmetic is attempted on such a string division by zero if an attempt to divide by zero is made BUGS
After argument processing by the shell, expr cannot tell the difference between an operator and an operand except by the value. If $a is an =, the command: expr $a = '=' looks like: expr = = = as the arguments are passed to expr (and they will all be taken as the = operator). The following works: expr X$a = X= Note: the match, substr, length, and index operators cannot themselves be used as ordinary strings. That is, the expression: example% expr index expurgatorious length syntax error example% generates the `syntax error' message as shown instead of the value 1 as you might expect. SunOS 5.10 6 Jun 2000 expr(1B)
All times are GMT -4. The time now is 03:28 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy